Answer:
y-7=1/4(x+5)
Step-by-step explanation:
y-3=-4(x+2)
y=-4x-8+3
y=-4x-5
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y-y1=m(x-x1)
y-7=m(x-(-5))
y-7=m(x+5)
perpendicular means negative reciprocal of the slope,
so the slope will be 1/4
y-7=1/4(x+5)
Answer:
the best thing to remember was in electricity prices in electricity prices in London in electricity and in electricity and gas prices and seek out the most efficient way of doing holiday shopping in a city with my own family and family and the food we are doing tasks and crewmate and our meals will kill the imposter of our children in our country in our lives that was close in a very long period and seek the same result as divisor in our society for me as divisor to make sure we will be the only people who have a right angle of life that was
Answer:
X = 4 pls mark me brainliest
Answer:
Check the explanation
Step-by-step explanation:
Going by the first attached image below we reject H_o against H_1 if obs.![T > t_{\alpha /2;n-1}](https://tex.z-dn.net/?f=T%20%3E%20t_%7B%5Calpha%20%2F2%3Bn-1%7D)
here obs.T=1.879
![\therefore obs.T \ngtr 2.447=t_{0.025;6}](https://tex.z-dn.net/?f=%5Ctherefore%20obs.T%20%5Cngtr%202.447%3Dt_%7B0.025%3B6%7D)
we accept
at 5% level of significance.
i.e there is no sufficient evidence to indicate that the special study program is more effective at 5% level of significance.
1.
this problem is simillar to the previous one except the alternative hypothesis.
Let X_i's denote the bonuses given by female managers and Y_i's denote the bonuses given by male managers.
we assume that
independently
We want to test ![H_0:\mu_{1}=\mu_{2} vs H_1:\mu_{1}\neq \mu_{2}](https://tex.z-dn.net/?f=H_0%3A%5Cmu_%7B1%7D%3D%5Cmu_%7B2%7D%20vs%20H_1%3A%5Cmu_%7B1%7D%5Cneq%20%5Cmu_%7B2%7D)
define ![D_i=X_i-Y_i , i=1(1)8](https://tex.z-dn.net/?f=D_i%3DX_i-Y_i%20%2C%20i%3D1%281%298)
now ![D_i\sim N(\mu _{1}-\mu _{2}=\mu _{D},\sigma _{1}^{2}+\sigma _{2}^{2}=\sigma _{D}^{2}) , i=1(1)8](https://tex.z-dn.net/?f=D_i%5Csim%20N%28%5Cmu%20_%7B1%7D-%5Cmu%20_%7B2%7D%3D%5Cmu%20_%7BD%7D%2C%5Csigma%20_%7B1%7D%5E%7B2%7D%2B%5Csigma%20_%7B2%7D%5E%7B2%7D%3D%5Csigma%20_%7BD%7D%5E%7B2%7D%29%20%2C%20i%3D1%281%298)
the hypothesis becomes
![H_0:\mu_{D}=0 vs H_1:\mu_{D}\neq 0](https://tex.z-dn.net/?f=H_0%3A%5Cmu_%7BD%7D%3D0%20vs%20H_1%3A%5Cmu_%7BD%7D%5Cneq%200)
in the third attached image, we use the same test statistic as before
i.e at 5% level of significance there is not enough evidence to indicate a difference in average bonuses .
I think it’s B but hopefully i’m right good luck