First, 126/32 so divide top and bottom by 2
126 / 2 = 63
32/2 = 16
answer
a = 16
and
b = 2
Answer: x= (-3)
Step-by-step explanation:
3/4 [x-1] = [-3]
(x-1) = (-3) × 4/3
X-1 = -4
X= -3
Could I have the choices?
This is based on understanding what dilation means in a graph transformation.
<em />
<em>The dilation from first square directly to sixth square will be; (x,y) -> (243, 243)</em>
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- In transformations, dilation of an object involves producing an image of the object that is the same shape but not the same size.
This means that if we want to dilate a square, we will produce a bigger square of a different size.
- We are told one corner of the first square she drew is (2, 2). This means that one side of the square is 2 units as the four sides of a square are equal.
- For the second square, she dilates the first one using (x, y) -> (3x, 3y).
This means the corner that was (2, 2) will now be (3 × 2), (3 × 2) = (6, 6)
- For the third square, it will be; (3 × 6), (3 × 6) = (18, 18)
- For the fourth square, it will be; (3 × 18), (3 × 18) = (54, 54)
- For the fifth square, it will be; (3 × 54), (3 × 54) = (162, 162)
- For the sixth square, it will be; (3 × 162), (3 × 162) = (486, 486)
Since first square was (2, 2), then it means dilation from first square directly to sixth square will be; (x,y) -> (486/2, 486/2)
⇒ (x,y) -> (243, 243)
Read more at; brainly.com/question/2523916
The value of "x" is 5.
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Given that,
A trapezium ABCD in which AB || CD such that
Now,










