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3 years ago

Find the area of the square ABCD. Need green and grey box! Please help me! Sorry for the bad quality lol

Mathematics

1 answer:

ivann1987 [24]3 years ago

3 0

Area = 196
a^2
14^2
196

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Espen predicted that he would sell 32 baseball caps but he actually sold 29 baseball caps which expression would find the percen

Gre4nikov [31]

Answer:

Step-by-step explanation:

This is the correct answer because the difference between 32 and 29 is 3 and the intial price is 32, Hence 3/32 (100)

6 0

3 years ago

Question in picture solve

dimulka [17.4K]

Answer:

x= 13.5

Step-by-step explanation:

f(x) = 2x + 9

f(x) = 36

Set the 2 equations equal to each other;

2x + 9 = 36

Subtract 9 from both sides;

2x = 27

Divide both sides by 2;

x = 13.5

<em>Check:</em>

f(x) = 2x + 9

f(13.5) = 2(13.5) + 9= 27 + 9 = 36

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3 years ago

How much should Tabatha budget monthly for insurance that costs $956.89 for the entire year?

elixir [45]

$79.74083 is the answer hope i help you

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3 years ago

The difference of a number p and 6

frez [133]

P-6 because you subtract the variable from the 6

7 0

3 years ago

Newton's law of cooling is:

Mnenie [13.5K]

Answer:

$t = \frac{ln(\frac{21}{59})}{-0.15}=6.887 hr$

So it would takes approximately 6.9 hours to reach 32 F.

Step-by-step explanation:

For this case we have the following differential equationÑ

$\frac{du}{dt}= -k (u-T)$

We can reorder the expression like this:

$\frac{du}{u-T} = -k dt$

We can use the substitution $w = u-T$ and $dw =du$ so then we have:

$\frac{dw}{w} =-k dt$

IF we integrate both sides we got:

$ln |w| = -kt +C$

If we apply exponential in both sides we got:

$w = e^{-kt} *e^c$

And if we replace w = u-T we got:

$u(t)= T + C_1 e^{-kt}$

We can also express the solution in the following terms:

$u(t) = (T_i -T_{amb}) e^{kt} +T_{amb}$

For this case we know that $k =-0.15 hr$ since w ehave a cooloing, $T_{i}= 70 F, T_{amb}=11F$ , we have this model:

$u(t) = (70-11) e^{-0.15t} +11$

And if we want that the temperature would be 32F we can solve for t like this:

$32 = 59 e^{-0.15 t} +11$

$21=59 e^{-0.15 t}$

$\frac{21}{59} = e^{-0.15 t}$

If we apply natural logs on both sides we got:

$ln (\frac{21}{59}) =-0.15 t$

$t = \frac{ln(\frac{21}{59})}{-0.15}=6.887 hr$

So it would takes approximately 6.9 hours to reach 32 F.

7 0

4 years ago