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Luba_88 [7]
3 years ago
9

Can you solve these problem and show work for each one of these please.

Mathematics
1 answer:
pychu [463]3 years ago
8 0
Consider this option.
Change the design according to the local requirements.

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$34.98 with 8.2 tax
Paraphin [41]

Answer:

$37.85

Step-by-step explanation:

Here the price is $34.98 and there's an 8.2% tax on that.  To obtain the after-tax amount due, multiply $34.98 by (1 + 0.082), or 1.082, obtaining:

1.082($34.98) = $37.85 (rounded to the nearest cent)

7 0
3 years ago
If 47400 dollars is invested at an interest rate of 7 percent per year, find the value of the investment at the end of 5 years f
Anni [7]

Answer:

Part A) Annual \$66,480.95  

Part B) Semiannual \$66,862.38  

Part C) Monthly \$67,195.44  

Part D) Daily \$67,261.54  

Step-by-step explanation:

we know that

The compound interest formula is equal to  

A=P(1+\frac{r}{n})^{nt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

so

Part A) Annual

in this problem we have  

t=5\ years\\ P=\$47,400\\ r=0.07\\n=1  

substitute in the formula above  

A=\$47,400(1+\frac{0.07}{1})^{1*5}  

A=\$47,400(1.07)^{5}  

A=\$66,480.95  

Part B) Semiannual

in this problem we have  

t=5\ years\\ P=\$47,400\\ r=0.07\\n=2  

substitute in the formula above  

A=\$47,400(1+\frac{0.07}{2})^{2*5}  

A=\$47,400(1.035)^{10}  

A=\$66,862.38  

Part C) Monthly

in this problem we have  

t=5\ years\\ P=\$47,400\\ r=0.07\\n=12  

substitute in the formula above  

A=\$47,400(1+\frac{0.07}{12})^{12*5}  

A=\$47,400(1.0058)^{60}  

A=\$67,195.44  

Part D) Daily

in this problem we have  

t=5\ years\\ P=\$47,400\\ r=0.07\\n=365  

substitute in the formula above  

A=\$47,400(1+\frac{0.07}{365})^{365*5}  

A=\$47,400(1.0002)^{1,825}  

A=\$67,261.54  

8 0
3 years ago
Two cars got an oil change at the same auto shop. The shop charges customers for each quart of oil plus a flat fee for labor. Th
dexar [7]

Answer:

The labor fee is $14.25, each quart of oil costs $2.25.

Step-by-step explanation:

Let $x be thee price of each quart of oil and $y be a flat fee for labor.

1. If the oil change for one car required 5 quarts of oil, then these 5 quarts cost $5x and together with a flat fee for labor it cost $25.50. Thus,

5x+y=25.50.

2. If the oil change for another car required 7 quarts of oil, then these 7 quarts cost $7x and together with a flat fee for labor it cost $30.00. Thus,

7x+y=30.00.

3. Subtract from the second equation the first one, then

7x+y-(5x+y)=30.00-25.50,\\ \\7x+y-5x-y=4.50,\\ \\2x=4.50,\\ \\x=\$2.25.

Substitute it into the first equation:

5\cdot 2.25+y=25.50,\\ \\y=25.50-11.25,\\ \\y=\$14.25.

The labor fee is $14.25, each quart of oil costs $2.25.

6 0
3 years ago
Which is greater 5.97 or 5.946????
Ivenika [448]

Answer:

5.97

Step-by-step explanation:

5 0
3 years ago
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Anyone have Plato edmentum? I need help with algebra 1 semester b plz helpppppp
Marianna [84]

Answer:

what is plato edmentum

Step-by-step explanation:

5 0
3 years ago
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