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Ne4ueva [31]
3 years ago
10

Graph the line with slope 3 and y-intercept -8.

Mathematics
1 answer:
Rama09 [41]3 years ago
3 0
There you go hope this helps

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Dalia saved $3000 last year. She said $600 in the month of January. What percent of the total amount of money she saved last yea
Anni [7]
1. We assume, that the number 3000 is 100% - because it's the output value of the task. 
<span>2. We assume, that x is the value we are looking for. </span>
<span>3. If 100% equals 3000, so we can write it down as 100%=3000. </span>
<span>4. We know, that x% equals 600 of the output value, so we can write it down as x%=600. </span>
5. Now we have two simple equations:
1) 100%=3000
2) x%=600
where left sides of both of them have the same units, and both right sides have the same units, so we can do something like that:
100%/x%=3000/600
6. Now we just have to solve the simple equation, and we will get the solution we are looking for.

7. Solution for 600 is what percent of 3000

100%/x%=3000/600
<span>(100/x)*x=(3000/600)*x       - </span>we multiply both sides of the equation by x
<span>100=5*x       - </span>we divide both sides of the equation by (5) to get x
<span>100/5=x </span>
<span>20=x </span>
<span>x=20
So 600 is 20% of 3000</span>
7 0
3 years ago
6.Find the equation of<br> the line:<br> through: (-2, 3) and<br> (1,5)
prohojiy [21]

Answer:

y=2/3x+4.3

Step-by-step explanation:

y=mx+c

(5-3)/(1--2)

2/3= gradient

y=2/3x +c

5=2/3(1)+c

-2/3

4.3=c

6 0
3 years ago
What is equivalent to 24b-34ab
jarptica [38.1K]
This is what I got as the answer, 2b x (12-17a)
6 0
3 years ago
A = 1011 + 337 + 337/2 +1011/10 + 337/5 + ... + 1/2021
egoroff_w [7]

The sum of the given series can be found by simplification of the number

of terms in the series.

  • A is approximately <u>2020.022</u>

Reasons:

The given sequence is presented as follows;

A = 1011 + 337 + 337/2 + 1011/10 + 337/5 + ... + 1/2021

Therefore;

  • \displaystyle A = \mathbf{1011 + \frac{1011}{3} + \frac{1011}{6} + \frac{1011}{10} + \frac{1011}{15} + ...+\frac{1}{2021}}

The n + 1 th term of the sequence, 1, 3, 6, 10, 15, ..., 2021 is given as follows;

  • \displaystyle a_{n+1} = \mathbf{\frac{n^2 + 3 \cdot n + 2}{2}}

Therefore, for the last term we have;

  • \displaystyle 2043231= \frac{n^2 + 3 \cdot n + 2}{2}

2 × 2043231 = n² + 3·n + 2

Which gives;

n² + 3·n + 2 - 2 × 2043231 = n² + 3·n - 4086460 = 0

Which gives, the number of terms, n = 2020

\displaystyle \frac{A}{2}  = \mathbf{ 1011 \cdot  \left(\frac{1}{2} +\frac{1}{6} + \frac{1}{12}+...+\frac{1}{4086460}  \right)}

\displaystyle \frac{A}{2}  = 1011 \cdot  \left(1 - \frac{1}{2} +\frac{1}{2} -  \frac{1}{3} + \frac{1}{3}- \frac{1}{4} +...+\frac{1}{2021}-\frac{1}{2022}  \right)

Which gives;

\displaystyle \frac{A}{2}  = 1011 \cdot  \left(1 - \frac{1}{2022}  \right)

\displaystyle  A = 2 \times 1011 \cdot  \left(1 - \frac{1}{2022}  \right) = \frac{1032231}{511} \approx \mathbf{2020.022}

  • A ≈ <u>2020.022</u>

Learn more about the sum of a series here:

brainly.com/question/190295

8 0
2 years ago
Read 2 more answers
bacteria colonies can increase by 73% every 2 days. if you start with 150 bacteria microorganisms, how large would the colony be
slavikrds [6]

Using an exponential function, it is found that the colony will have 1344 bacteria after 8 days.

<h3>What is an exponential function?</h3>

An increasing exponential function is modeled by:

A(t) = A(0)(1 + r)^t

In which:

  • A(0) is the initial value.
  • r is the decay rate, as a decimal.

Considering the initial amount of 150, and the growth rate of 73% each 2 days, the equation is given by:

A(t) = 150(1.73)^{\frac{t}{2}}

Hence, after 8 days, the amount of bacteria is given by:

A(8) = 150(1.73)^{\frac{8}{2}} = 1344

More can be learned about exponential functions at brainly.com/question/25537936

#SPJ1

6 0
2 years ago
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