The answer is D. 9 yd. 7 in.

Let's sum all up:
1yd 2ft 6in + 2yd 1ft 5in + 4yd 2ft 8in

Sum inches:
6 + 5 + 8 = 19 in
12 in = 1 ft
19 in = 1ft 7in

Sum feet:
2 + 1 + 2 + 1(from inches) = 6 ft
3ft = 1yd
6ft = 2y

Sum yards:
1 + 2 + 4 + 2(from feet) = 9 yd

4 0

3 years ago

While conducting experiments, a marine biologist selects water depths from a uniformly distributed collection that vary between

mr_godi [17]

Answer: The expected value of the water depth is 4.5 m.

Step-by-step explanation:

Let x be a random variable which is uniformly distributed in interval [a,b] .

Then the mean of the distribution is ghiven by :-

$E(x)=\dfrac{a+b}{2}$

Given : While conducting experiments, a marine biologist selects water depths from a uniformly distributed collection that vary between 2.00 m and 7.00 m.

Then, the expected value of the water depth = $\dfrac{2+7}{2}=\dfrac{9}{2}=4.5$