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Orlov [11]
3 years ago
7

If 10/4 = 14/x what is x?

Mathematics
2 answers:
docker41 [41]3 years ago
7 0
Is there answer choices? Because if you do 10/4=2.5 and if you do 14/2.5 you get 5.6
cluponka [151]3 years ago
6 0
Answer: 5.6

Explanation:

1) set the proportion:

 10        14
----- =   -----
  4           x

2) clear the unknown, x

10x = 14(4)

=> 10x = 56

=> x = 56 / 10

=> x = 5.6
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a linear system with no solution consists of the equation y=4x-3 and a second equation of the form y=mx+b. what can you say abou
Akimi4 [234]
The value of m must be 4 and the value of b must NOT be -3.

No matter what numbers they involve, two equations with the SAME slope (m) and a DIFFERENT y-intercept (b) have no solution.  This is because they form parallel lines, never crossing and therefore never giving a solution.
6 0
3 years ago
Write <br> –1.2 as a mixed number.
Luden [163]

Answer:

-1 1/5

Step-by-step explanation: cause calculator

7 0
4 years ago
Suppose that the functions r and s are defined for all real numbers x as follows. =rx−x5 =sx+2x3 write the expressions for ·rsx
PolarNik [594]

Although the question's print is not clear, to the best of my knowledge, as I can see, We are given that:

r(x)=-x^5 and s(x)=2x^3

No, we know that, by definition:

(r.s)(x)=r(x)\times s(x)

\therefore (r.s)(x)=-x^5\times 2x^3=-2x^8

Thus, for the functions r and s which are defined for all real numbers x, the answer to the question asked is:

(r.s)(x)=-2x^8

8 0
3 years ago
*FIRST ANSWER GETS BRAINLIEST*
svet-max [94.6K]

The other solution to the equation is -3.

Step-by-step explanation:

Given equation is;

5x²+bx+12=0

One solution is -4/5

We will put this solution in Eqn to get the value of b first,

5(\frac{-4}{5})^2+b(\frac{-4}{5})+12=0\\5(\frac{16}{25})+(\frac{-4b}{5})+12=0\\\frac{16}{5}-\frac{-4b}{5}=-12\\

Multiplying each term by 5

5*(\frac{16}{5})-\frac{-4b}{5}*5=-12*5\\16-4b=-60\\-4b=-60-16\\-4b=-76

Dividing both sides by -4

\frac{-4b}{-4}=\frac{-76}{-4}\\b=19

Putting b=19 in given Eqn

5x²+19x+12=0

Here,

a=5 , b=19 , c=12

Using quadratic formula,

x=\frac{-b\±\sqrt{b^2-4ac}}{2a}\\x=\frac{-(19)\±\sqrt{(19)^2-4(5)(12)}}{2(5)}\\\\x=\frac{-19\±\sqrt{361-240}}{10}\\\\x=\frac{-19\±11}{10}\\

Either,                   or,

x=\frac{-19+11}{10},\ \ \ \ \ \ x=\frac{-19-11}{10}\\x=\frac{-8}{10},\ \ \ \ \ \ \ \ \ x=\frac{-30}{10}\\x=\frac{-4}{5},\ \ \ \ \ \ \ \ \ \ x= -3

The other solution to the equation is -3.

Keywords: linear equation, quadratic formula

Learn more about quadratic formula at:

  • brainly.com/question/7128279
  • brainly.com/question/6788996

#LearnwithBrainly

6 0
3 years ago
-2.3z = -13.8 <br> I need to show work lol
dsp73

Here are your answers.

it's made by computer.

<em>-</em><em> </em><em>BRAINLIEST</em><em> answerer</em>

6 0
3 years ago
Read 2 more answers
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