(88sin20)(t - 16t²) = 0
(8(0.3090169944)(t - 16t²) = 0
(2.472135955)(t - 16t²) = 0
2.472135955t - 39.55417528t² = 0
Answer:
Step-by-step explanation:
Hello!
The variable of interest, X: height of women at a college, has an approximately normal distribution with mean μ= 65 inches and standard deviation σ= 1.5 inches.
You need to look for the value of height that marks the bottom 20% of the distribution, i.e. the height at the 20th percentile of the normal curve, symbolically:
P(X≤x₀)= 0.20
To know what value of height belongs to the 20% of the distribution, you have to work using the standard normal distribution and then reverse the standardization with the population mean and standard deviation to reach the value of X. So the first step is to look for the Z-value that accumulates 20% of the distribution:
P(Z≤z₀)=0.20
z₀= -0.842
z₀= (x₀-μ)/σ
z₀*σ= (x₀-μ)
x₀= (z₀*σ)+μ
x₀= (-0.842*1.5)+65
x₀= 63.737 inches
I hope it helps!
Answer:
9
gallons of water
Step-by-step explanation:
To find how many gallons of water go down each minute, divide the total number of gallons of water by the number of minutes it takes to drain:
70/7.5
= 9
So, 9 gallons of water go down the drain each minute
