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3 years ago

6

The points scored on a test for a sample of

1 answer:

jasenka [17]3 years ago

5 0

Answer:

The mean is 42.6

Step-by-step explanation:

$6+90+16+80+15 + 70 + 4 + 60 = 341 \\ there \: are \: 8 \: numbers \: in \: total \: so \: you \: divide \: the \: sum \\ by \: 8. \\ 341 \div 8 = 42.625 \\ mean≈42.6$

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Which statement is true

Yakvenalex [24]

Answer:

I think its. u must check with calculator

8 0

2 years ago

Not all visitors to a certain company's website are customers. In fact, the website administrator estimates that about 5% of all

Gnom [1K]

Answer:

0.0135 = 1.35% probability that, in a random sample of 4 visitors to the website, exactly 2 actually are looking for the website.

Step-by-step explanation:

For each visitor of the website, there are only two possible outcomes. Either they are looking for the website, or they are not. The probability of a customer being looking for the website is independent of other customers. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

5% of all visitors to the website are looking for other websites.

So 100 - 5 = 95% are looking for the website, which means that $p = 0.95$

Find the probability that, in a random sample of 4 visitors to the website, exactly 2 actually are looking for the website.

This is P(X = 2) when n = 4. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = x) = C_{4,2}.(0.95)^{2}.(0.05)^{2} = 0.0135$

0.0135 = 1.35% probability that, in a random sample of 4 visitors to the website, exactly 2 actually are looking for the website.

5 0

3 years ago

The arena at the Berry Center holds 9,500 people. During one of the graduation ceremonies, 95% of the seats were occupied. How m

motikmotik

Answer:

9,025

Step-by-step explanation:

9,500 multiplied by 0.95

3 0

4 years ago

A gardener planted some seedlings at equal distances apart along a straight road. The 3rd seedling and the 5th seedling were 9/1

ratelena [41]

Answer:

Answer:

17 seedlings

Step-by-step explanation:

Given;

The seedlings are at an equal distance in a straight line.

Distance between 3rd seedling and 5th seedling = 9/10 m

So, distance between 3rd seedling and 4th seedling = 9/10 ÷ 2 = 9/20 m

So, the distance between two seedlings in a line = 9/20 m

The given distance between 2nd seedling and the last seedling = 6 3/4 m = 27/4 m

8 0

2 years ago

What is the equation of the line containing the points (3, 1), (9, 3), and (27, 9)?

lutik1710 [3]

From the given points that are (3,1),(9,3),(27,9), we can say that x is three times of y. That is

x= 3y

And we need to solve for y. For that, we need to get rid of 3 from the right side by dividing both sides by 3 . And on doing so , we will get

$\frac{x}{3} = \frac{3y}{3}$

$\frac{x}{3}=y$

or

$y=\frac{x}{3}$

7 0

3 years ago