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artcher [175]
4 years ago
7

Need help with these questions

Mathematics
2 answers:
bogdanovich [222]4 years ago
7 0

Answer:

9. C = -32y + 72

10. B 12(3/8x) + 9(1/3)

iogann1982 [59]4 years ago
6 0

Answer:

Question 9) c.  -32y + 72

Question 10) B.  12  3/8 x + 9 1/3

Step-by-step explanation:

<u>Question 9</u>

-8(4y - 9)

First open the parenthesis

-8(4y - 9) = (-8×4y) - (-8×9)

               = -32y + 72

<u>Question 10</u>

3(4x - 2/9) + 1/2(3/4x + 20)

The first thing is to open the parenthesis:

3(4x - 2/9) + 1/2(3/4x + 20) =12x - 6/9 + (3/8)x + 1/40

            Put the like erms together

3(4x - 2/9) + 1/2(3/4x + 20) =12x - 6/9 + (3/8)x + 10

                                            = 12x + (3/8)x - 6/9 + 10

                                           = (99/8)x - 2/3 + 10

                                            = (99/8)x - 28/3

                                             = 12  3/8 x + 9 1/3

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Answer:

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Step-by-step explanation:

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Can someone please explain Question 8, and how to do it? Thank you!!:)
insens350 [35]

Proof for the equations are given below.

Step-by-step explanation:

  • Step 1: The diagram is made up of 1 square and 4 rectangles, and the whole figure is a square. So the area of the larger square (figure) must be equal to the sum of the areas of the 4 rectangles and 1 square. Find the area of the figure or the larger square.

Area of a square = (side length)²

Here, the length of the side of the larger square = a + b

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  • Step 2: Find the sum of the areas of the 1 square and 4 rectangles.

Here, the side of the square = a - b

⇒ Area of the square (in the center) = (a - b)²

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Now, both these areas are the same.

⇒ (a - b)² + 4ab = (a + b)²

  • Step 3: Expand the above equation.

Left Hand Side =  (a - b)² + 4ab = a² - 2ab + b² + 4ab = a² + 2ab + b²

                                                    = (a + b)²

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Use the Pythagorean Theorem to find the missing length in the right triangle
Gelneren [198K]

Answer:

it depends

Step-by-step explanation:

If 17 is the hypotenuse

c=17\\\\b=12\\\\a=?\\\\c^{2} =a^2+b^2\\\\17^2=a^2+12^2\\\\17^2-12^2=a^2\\\\(17-12)(17+12)=a^2\\\\5(27)=a^2\\\\a=\sqrt{9*3*5} \\\\a=3\sqrt{15} \\\\a=11.6

if you are looking for the hypotenuse

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