so, x =

and y =

Hence, the answer is the first one.
I think you're asking if it's possible to have a cube root, fifth root, 7th root, etc of a number as a solution to f(x). The answer is yes it's possible.
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Example:
f(x) = x^3 - 29
This function has one real-number root of
(cube root of 29) and the other two roots are complex or imaginary roots.
Step-by-step explanation:
m<V+m<W+m<X=180° (sum of the interior angles)
m<V+20°+90°=180°
m<V=180-110°=70°


