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Zielflug [23.3K]
3 years ago
7

What are the distances from the point (x,y) to the focus of the parabola and the directrix, select two answers

Mathematics
1 answer:
yulyashka [42]3 years ago
6 0

Answer:

3,5

Step-by-step explanation:

axis

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A Microgates Industries bond has a 10 percent coupon rate and a $1,000 face value. Interest is paid semiannually, and the bond h
Usimov [2.4K]

Answer:

a. $849.45

Step-by-step explanation:

In the above question, we are given the following information

Coupon rate = 10%

Face value = 1000

Maturity = n = 20 years

t = number of periods = compounded semi annually = 2

Percent yield = 12% = 0.12

Bond Value formula =

C/t × ([1 -( 1/ 1 + r/t)-^nt ÷] r/t) +( F/ (1 + r/t)^nt)

C = coupon rate × face value = 10% × 1000 = 100

Bond value:

= 100/2 × ( [1 - (1 /1 + 0.12/2)^-20×2]÷ 0.12/2)+ (1000/( 1 + 0.12/2)^20×2

= 50 × ( [1 - (1 /1 + 0.06) ^40] ÷ 0.06) + ( 1000/ (1 + 0.06) ^40

= 50 × ( [1 - (1/ (1.06) ^40] ÷ 0.06 ) + (1000/(1.06)^40)

= 50 × 15.046296872 + 97.222187709

= $849.45

Bond value = $849.45

8 0
3 years ago
Help me plz thanksss
natulia [17]

Answer:

0.5j+19

Step-by-step explanation:

6 0
3 years ago
Four friends go to an amusement arcade.
galben [10]

<u><em>Answer:</em></u>

<u>The rule is: </u>

T(x) = 8x + 20

<em><u>Explanation:</u></em>

<u>We are given that:</u>

<u>The rule for the amount that one friend pays is:</u>

C(x) = 2x + 5

<u>Now, we know that:</u>

Each of the four friends will pay the entry fee which is $5 per person

The 4 friends will play the same number of games represented by x

<u>This means that:</u>

We can simply get the rule for the total amount to be paid by the four friends (T(x)) by multiplying the amount paid by each friend by 4

<u>This means that:</u>

T(x) = 4 * C(x)

T(x) = 4(2x + 5)

T(x) = 8x + 20

Hope this helps :)

4 0
4 years ago
Use the diagram to copy and complete the statement. (#12, 14, 16)
Sergio [31]

11 is the biggest and the 22

8 0
4 years ago
Simplify . (1/c + 1/h)/(1/(c ^ 2) - 1/(r ^ 2))
Marrrta [24]

Answer:

\frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}

Step-by-step explanation:

\frac{\frac{1}{c}+\frac{1}{h}}{\frac{1}{c^2}-\frac{1}{r^2}}

Combine \frac{1}{c} + \frac{1}{h}

\frac{\frac{h+c}{ch}}{\frac{1}{c^2}-\frac{1}{r^2}}

Combine the bottom, too.

=\frac{\frac{h+c}{ch}}{\frac{r^2-c^2}{c^2r^2}}

Apply the fraction rule

=\frac{\left(h+c\right)c^2r^2}{ch\left(r^2-c^2\right)}

Cancel

=\frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}

Therefore, \frac{\left(\frac{1}{c}+\frac{1}{h}\right)}{\left(\frac{1}{\left(c^2\right)}-\frac{1}{\left(r^2\right)}\right)}:\quad \frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}

5 0
3 years ago
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