Answer:
1 and - 1
Step-by-step explanation:
The equation of a line passing through the origin is
y = mx ( m is the slope ( gradient ) )
y = x ← is in this form
with gradient m = 1
Parallel lines have equal gradients
Then the gradients of lines parallel to the given line is 1
Given a line with gradient m then the gradient of a line perpendicular to it is
= - 
= - 
= - 1
Then the gradients of lines perpendicular to this line is - 1
Answer:
Step-by-step explanation:
the line grath is your answer
YOU WELCOME
Using product rule;
f(x)=(1+6x²)(x-x²)
f'(x)=(12x)(x-x²) + (1-2x)(1+6x²) = 12x² -12x³ +1 +6x² -2x -12x³ = -24x³ +18x² -2x +1
Solving the bracket first;
f(x)=(1+6x²)(x-x²) = x -x² +6x³ -6x^4
f'(x)= 1 -2x +18x² -24x³ = -24x³ +18x² -2x +1
Answer:
The answer is
Step-by-step explanation:
To find an equation of a line when given the slope and a point we use the formula
From the question we have
We have the final answer as
<h3>y = -2x</h3>
Hope this helps you
Answer:
G^Y boyyyy
Step-by-step explanation:
no because the answer will not apear until you pay attention in class bum
