How many zeros does the function f(x) = 3x12 − 17x8 + 11x4 − 6x + 23 have?
1 answer:
How many zeros does the function f(x) = 3x12 − 17x8 + 11x4 − 6x + 23 have?
<span>Answer: the third option (12 zeroes..). </span>
<span>Use ^ to denote an exponent.. </span>
<span>f(x) = 3x^12 - 17x^8 + 11x^4 - 6x + 23.. </span>
<span>We know from that fact that the number of zeroes (real or complex) in a polynomial is the same as the degree of the polynomial.. </span>
<span>The degree is the greatest/highest power of the terms, which in this case is 12 (since 12 is the greatest exponent..).. </span>
<span>The degree is 12, thus it means there are 12 zeroes.. </span>
<span>Answer: the third option (12 zeroes)...</span>
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The correct answer would be B.
Answer:
AD=5.82 units
Step-by-step explanation:
tan 31=3/BD
0.6009=3/BD
BD=5
AD^2=3^2 + 5^2
AD^2=9+25=34
AD=5.82
I believe it’s B
Your trying to find the area of the triangle of the two numbers of that makes any kind of sense
