3 years ago

How do i find BC? Khan Academy

Mathematics

1 answer:

Brrunno [24]3 years ago

6 0

Answer:

using cos=adjacent/hypotenuse

Step-by-step explanation:

in this case cos(60)=x/4√3

x=cos(60)*4√3

x=3.46

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3 years ago

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Find the arc length of the curve on the given interval. Parametric Equations Interval x = 6t + 5, y = 7 − 5t −1 ≤ t ≤ 3

laiz [17]

Answer:

31.241

Step-by-step explanation:

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dx/dt = 6

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L = ∫ $\sqrt{(\frac{dx}{dt} )^2 + (\frac{dy}{dt})^2 dt }$

= $\int\limits^3_ {-1} \, \sqrt{36 + 25 dt}$

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8 0

3 years ago