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mart [117]
3 years ago
12

GCF of 30 48 and 72​

Mathematics
1 answer:
USPshnik [31]3 years ago
7 0
The greatest common factor of those numbers is 8.
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11089 divided by 13​
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Answer:

853

Step-by-step explanation:

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Tye required equation will be

Y = 50c+200

Step-by-step explanation:

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HELP! How many triangles can be made from the following three lengths: 1.6 centimeters, 7.4 centimeters, and 5.9 centimeters?
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Answer: one

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4 0
3 years ago
What’s the largest fraction: 7/8, 5/8, 7/13, and 11/19
garik1379 [7]

Answer:

7/8

Step-by-step explanation:

7/8 = 0.875

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4 0
3 years ago
Two children, Ferdinand and Isabella, are playing with a water hose on a sunny summer day. Isabella is holding the hose in her h
wolverine [178]

Answer:

 f = 0.84 or 84%

Step-by-step explanation:

Given:

- Original constant velocity of water v_o = 3.5 m/s

- The original diameter of the hose opening d_o = 1.5 cm

- The total vertical distance y(f) = 1.0 m

- The total range x(f) = 10.0 m

Find:

What fraction of the original area does Isabella has to reduce or pinch so the water can cover the entire range.

Solution:

- We will assume the flow of water as a stream of particles that follow a path of single point.

- Using second kinematic equation in the vertical direction and compute the time it takes the water to reach the ground:

                                  y(t) = y(0) + v_y*t + 0.5*gt^2

Where, y(0) = v_y = 0,

                                  1.0 = 0.5*g*t^2

                                  t = sqrt ( 2*1 / 9.81 )

                                  t = 0.4515 s

- Now we will use the second equation of motion for the x- direction motion:

                                 x(t) = x(0) + v_x*t

Where, x(0) = 0,

                                 10 = 0 + v_x*(0.4515)

                                 v_x = 10 / 0.4515 = 22.1 m/s

- We have calculated the minimum velocity required to reach the range from isabella and ferdinand.

- We will use the continuity equation to compute the area required for the velocity calculated v_x = 22.1 m/s:

                                A_f*v_x = A_o*v_o

                                A_f = A_o*v_o / v_x

                                A_f = pi*0.015^2*3.5 / 4*22.1

                                A_f = 1.12 * 10^-4 m^2

- The fraction f of the reduction of area is:

                                f = (A_o - A_f) / A_o

                                f = (7.068*10^-8 - 1.12*10^-4) / (7.068*10^-8)

                               f = 0.84 or 84%

4 0
3 years ago
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