amber deposits $870 in an account that has a simple interest rate of 8% per year. After 5 years, how much interest will Amber ha
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Answer:
The graph you have is wrong. This is the right graph.
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Answer:
0.6173 = 61.73% probability that the product operates.
Step-by-step explanation:
For each integrated circuit, there are only two possible outcomes. Either they are defective, or they are not. The integrated circuits are independent. This means that we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
An electronic product contains 48 integrated circuits.
This means that
The probability that any integrated circuit is defective is 0.01.
This means that
The product operates only if there are no defective integrated circuits. What is the probability that the product operates?
This is P(X = 0). So
0.6173 = 61.73% probability that the product operates.
Answer:
Required Probability = 0.1283 .
Step-by-step explanation:
We are given that at Meadow brook Hospital, the mean weight of babies born to full-term pregnancies is 7 lbs with a standard deviation of 14 oz.
Firstly, standard deviation in lbs = 14 ÷ 16 = 0.875 lbs.
Also, Birth weights of babies born to full-term pregnancies follow roughly a Normal distribution.
Let X = mean weight of the babies, so X ~ N()
The standard normal z distribution is given by;
Z = ~ N(0,1)
where, X bar = sample mean weight
n = sample size = 4
Now, probability that the average weight of the four babies will be more than 7.5 lbs = P(X bar > 7.5 lbs)
P(X bar > 7.5) = P( >
) = P(Z > 1.1428) = 0.1283 (using z% table)
Therefore, the probability that the average weight of the four babies will be more than 7.5 lbs is 0.1283 .