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Brut [27]
3 years ago
11

16(a - 2) + 3(10 - a)

Mathematics
2 answers:
julia-pushkina [17]3 years ago
8 0
16(a-2)+3(10-a)
16a-32+30-3a
-3a
13a-32+30
13a-2
balu736 [363]3 years ago
6 0
I believe it's -2 but i'm not 100% sure.
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Solve the system by substitution <br> y = 6x -24<br> y = -2x
Katen [24]

Answer: x = 3, y = -6

Step-by-step explanation:

Substitute the y into the equation to get -2x=6x-24

8x=24 so x = 3. Then plug x=3 into the second equation to get y = -6

8 0
3 years ago
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Complete the solution of the equation. find the value of y when x equals 1. <br><br>9x +7y= -12​
Taya2010 [7]

Answer:

y=-3

Step-by-step explanation:

Given Equation:  

                            9x +7y=-12\\             y=?       at    x= 1

Putting the given value of 'x' in the equation:

                            9(1) +7y=-12\\\\9+7y=-12\\\\7y=-12-9\\\\7y=-21\\\\y=-\frac{21}{7} \\y=-3

At x=1, the value of y is y=-3

6 0
3 years ago
You are selling a mobile app for $10 per user per month.if you get 7 users every month starting with 10 in the first month.how m
Ahat [919]

Selling price of app per user = $10 per month

Total no. of user in first month = 10

To tal no. of user added per month = 7

We have to find how much money is earned in one year

So the formula is n/2 * (2a +(n-1)d)

Here we have n = 12 which is total no. of months

a = 100 , which is money earned in one month

d = 70 , which is increase in money earned per month

So money earned in a year comes out to be 5820

4 0
3 years ago
John looked at his bank account and noticed that he had $2,029.90 in his account. All that he could remember is that he created
Over [174]

We will have that for the previous year, he had in the account:

m_{y6}=2029.90-\frac{2029.90\cdot6}{100}\Rightarrow m_{y6}=1908.106

For the year previous to that one, he had:

m_{y5}=1908.106-\frac{1908.106\cdot6}{100}\Rightarrow m_{y5}=1793.61964

For the previous year to that, he had:

m_{y4}=1793.61964-\frac{1793.61964\cdot6}{100}\Rightarrow m_{y4}=1686.002462

For the year previous to that one, he had:

m_{y3}=1686.002462-\frac{1686.002462\cdot6}{100}\Rightarrow m_{y3}=1584.842314

For the second year that the money was in the account, there was:

m_{y2}=1584.842314-\frac{1584.842314\cdot6}{100}\Rightarrow m_{y2}=1489.751775

And the orinial ammount of money that was in the account was:

m_{y1}=1489.751775-\frac{1489.751775\cdot6}{100}\Rightarrow m_{y1}=1400.366669

From this, we know that Jhon had originally $1400.37 in the bank account.

6 0
1 year ago
Z 3 - 2z 2 + 9z - 18.
aev [14]

group the 1st 2 terms and last 2 terms:

(Z63 -2z^2) + (9z-18)

factor out GCF:

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now factor the polynomial:

(z-2) (z^2+9)

5 0
3 years ago
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