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2 years ago

Ty sold 50 tickets this is 40% of how many he has to sell how many tickets must he sell

Mathematics

1 answer:

dsp732 years ago

3 0

50 tickets out of ?
40 % out of 100
50 x 100=5000
5000/40=125
He has to sell 125 tickets total. Hope this helped!

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Solve the system of equations. y=7x y=2x + 20 x=? y=?

alekssr [168]

X=4, y=28. 7x=2x+20, so subtract 2x from both sides and you’ll get 5x=20. Divide both sides by 5 and you’ll get x=4. Substitute this into the other equations and they will both equal 28.

6 0

2 years ago

2+2+4+32 please solve :D

Arturiano [62]

Answer:

Step-by-step explanation:

2+2 = 4

4+4 = 8

8+32= 40

4 0

3 years ago

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Convert the Cartesian equation (x 2 + y 2)2 = 4(x 2 - y 2) to a polar equation.

SashulF [63]

ANSWER

${r}^{2} = 4 \cos2\theta$

EXPLANATION

The Cartesian equation is

${( {x}^{2} + {y}^{2} )}^{2} = 4( {x}^{2} - {y}^{2} )$

We substitute

$x = r \cos( \theta)$

$y = r \sin( \theta)$

and

${x}^{2} + {y}^{2} = {r}^{2}$

This implies that

${( {r}^{2} )}^{2} = 4(( { r \cos\theta) }^{2} - {(r \sin\theta) }^{2} )$

Let us evaluate the exponents to get:

${r}^{4} = 4({ {r}^{2} \cos^{2}\theta } - {r}^{2} \sin^{2}\theta)$

Factor the RHS to get:

${r}^{4} = 4{r}^{2} ({ \cos^{2}\theta } - \sin^{2}\theta)$

Divide through by r²

${r}^{2} = 4 ({ \cos^{2}\theta } - \sin^{2}\theta)$

Apply the double angle identity

$\cos^{2}\theta -\sin^{2}\theta= \cos(2 \theta)$

The polar equation then becomes:

${r}^{2} = 4 \cos2\theta$

7 0

3 years ago

Solve the inequality for x. show each step of the solution -12x-0.4>0.2(36.5x+80)-55

Darina [25.2K]

Let's solve your inequality step-by-step.

−12x−0.4>0.2(36.5x+80)−55

Step 1: Simplify both sides of the inequality.

−12x−0.4>7.3x−39

Step 2: Subtract 7.3x from both sides.

−12x−0.4−7.3x>7.3x−39−7.3x

−19.3x−0.4>−39

Step 3: Add 0.4 to both sides.

−19.3x−0.4+0.4>−39+0.4

−19.3x>−38.6

Step 4: Divide both sides by -19.3.

−19.3x

−19.3

−38.6

−19.3

x<2

Answer:

x<2

8 0

3 years ago

PLEASE HELP! 20 POINTS 1) A ball is thrown starting at a time of 0 and a height of 2 meters. The height of the ball follows the

drek231 [11]

Answer:

1) The height of the ball from 0 to 5 seconds are;

At t = 0 second, height = 2

At t = 1 second, height h = 22.1

At t = 2 seconds, height h = 32.4

At t = 3 seconds, height h = 32.9

At t = 4 seconds, height h = 23.6

At t = 5 seconds, height h = 4.5

2) The correct option is;

D. -16·t² + 25·t + 1

Step-by-step explanation:

1) The equation of motion of the ball is given as follows;

H(t) = -4.9·t² + 25·t + 2

The height of the ball from 0 to 5 seconds are;

H(0) = -4.9×(0)² + 25×(0) + 2 = 2

H(1) = -4.9×(1)² + 25×(1) + 2 = 22.1

H(2) = -4.9×(2)² + 25×(2) + 2 = 32.4

H(3) = -4.9×(3)² + 25×(3) + 2 = 32.9

H(4) = -4.9×(4)² + 25×(4) + 2 = 23.6

H(5) = -4.9×(5)² + 25×(5) + 2 = 4.5

Therefore, we have;

The height of the ball are

At t = 0 second, height = 2

At t = 1 second, height h = 22.1

At t = 2 seconds, height h = 32.4

At t = 3 seconds, height h = 32.9

At t = 4 seconds, height h = 23.6

At t = 5 seconds, height h = 4.5

2) Given that the equation of the ball is that of a projectile motion, such as follows;

h = h₀ + v₀·sin(θ₀)·t - 1/2·g·t² which is equivalent to h = -1/2·g·t²+ h₀+v₀·sin(θ₀)·t

it is best represented by the quadratic equation of an upside down parabola which is option D. -16·t² + 25·t + 1

6 0

3 years ago