1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
GenaCL600 [577]
3 years ago
7

Pls help! Include the unit.

Mathematics
1 answer:
Bezzdna [24]3 years ago
4 0
She swim 0.85 kilometers
You might be interested in
Find the exact value of (1 7/9)^1/2
sweet [91]

I assume you mean the mixed number 1 + 7/9.

As an improper fraction, we have

1   7/9 = 1 + 7/9 = 9/9 + 7/9 = (9 + 7)/9 = 16/9

Then the square root of this is

√(1   7/9) = √(16/9) = √(4²/3²) = √((4/3)²) = 4/3

3 0
2 years ago
1. From a circular sheet of radius 18 cm, two circles of radii 4.5 cm and a rectangle of length 4 cm and breadth 1 cm are remove
telo118 [61]

Area of a circle = PI x r^2

Area of sheet = 22/7 x 18^2 = 1,018.29 square cm.

Area of small circle = 22/7 x 4.5^2 = 63.64 square cm.

There are 2 small circles so total area of the circles are 63.64 x 2 = 127.28 square cm.

Area of rectangle = l x w = 4 x 1 = 4 square cm.

Total area of cutouts = 127.28 + 4 = 131.28 square cm.

Area of sheet left, subtract area of cutouts fro area of sheet:

1018.29 - 131.28 = 887.01 square cm.

Round everything as needed.

4 0
3 years ago
Pretty please for a homie
leonid [27]
Slope is -2
_______
Y+4=-2x+8
Y=-2x+4
3 0
3 years ago
A company plans to enclose three parallel rectangular areas for sorting returned goods. The three areas are within one large rec
Svetlanka [38]

Answer:

The largest total area that can be enclosed will be a square of length 272 yards.

Step-by-step explanation:

First we get the perimeter of the large rectangular enclosure.

Perimeter of a rectangle =2(l + w)

Perimeter of the large rectangular enclosure= 1088 yard

Therefore:

2(L+W)=1088

The region inside the fence is the area

Area: A = LW

We need to solve the perimeter formula for either the length or width.

2L+ 2W= 1088 yd

2W= 1088– 2L

W = \frac{1088-2L}{2}

W = 544–L

Now substitute W = 544–L into the area formula

A = LW

A = L(544 – L)

A = 544L–L²

Since A is a quadratic expression, we re-write the expression with the exponents in descending order.

A = –L²+544L

Next, we look for the value of the x coordinate

L= -\frac{b}{2a}

L= -\frac{544}{2X-1}

L=272 yards

Plugging L=272 yards into the calculation for area:

A = –L²+544L

A(272)=-272²+544(272)

=73984 square yards

Thus the largest area that could be encompassed would be a square where each side has a length of 272 yards and a width of:

W = 544 – L

= 544 – 272

= 272 yards

7 0
3 years ago
How many 3-person committees can be formed in a club with 8 members??
earnstyle [38]
=8C3
=8!/(3!*5!)
=56 ways
7 0
3 years ago
Other questions:
  • A relation must have exactly one output for every input. T/F?
    5·2 answers
  • Geometry help please
    7·1 answer
  • What’s |z-15|+5c+j z=10 c=-2 j=-4
    9·1 answer
  • What's the answer to this.
    13·1 answer
  • HELP ME please :) Please
    12·1 answer
  • Find the midpoint of AB if A is (-3,-3) and B is (6,6)?
    14·1 answer
  • Is 1 over 3 irrational or rational?
    5·2 answers
  • Help which one <br><br> A . (1/2)(4)(3)<br> B . (1/2)(4)(11)<br> C . (1/2)(4)(8)<br> D . (1/2)(8)(4)
    10·1 answer
  • I need help on the ones I did not do
    11·1 answer
  • Hi please help !!! With steps as well please!
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!