I assume you mean the mixed number 1 + 7/9.
As an improper fraction, we have
1 7/9 = 1 + 7/9 = 9/9 + 7/9 = (9 + 7)/9 = 16/9
Then the square root of this is
√(1 7/9) = √(16/9) = √(4²/3²) = √((4/3)²) = 4/3
Area of a circle = PI x r^2
Area of sheet = 22/7 x 18^2 = 1,018.29 square cm.
Area of small circle = 22/7 x 4.5^2 = 63.64 square cm.
There are 2 small circles so total area of the circles are 63.64 x 2 = 127.28 square cm.
Area of rectangle = l x w = 4 x 1 = 4 square cm.
Total area of cutouts = 127.28 + 4 = 131.28 square cm.
Area of sheet left, subtract area of cutouts fro area of sheet:
1018.29 - 131.28 = 887.01 square cm.
Round everything as needed.
Slope is -2
_______
Y+4=-2x+8
Y=-2x+4
Answer:
The largest total area that can be enclosed will be a square of length 272 yards.
Step-by-step explanation:
First we get the perimeter of the large rectangular enclosure.
Perimeter of a rectangle =2(l + w)
Perimeter of the large rectangular enclosure= 1088 yard
Therefore:
2(L+W)=1088
The region inside the fence is the area
Area: A = LW
We need to solve the perimeter formula for either the length or width.
2L+ 2W= 1088 yd
2W= 1088– 2L
W = 
W = 544–L
Now substitute W = 544–L into the area formula
A = LW
A = L(544 – L)
A = 544L–L²
Since A is a quadratic expression, we re-write the expression with the exponents in descending order.
A = –L²+544L
Next, we look for the value of the x coordinate


L=272 yards
Plugging L=272 yards into the calculation for area:
A = –L²+544L
A(272)=-272²+544(272)
=73984 square yards
Thus the largest area that could be encompassed would be a square where each side has a length of 272 yards and a width of:
W = 544 – L
= 544 – 272
= 272 yards