Answer:
Yes!
Step-by-step explanation:
Because it passes the vertical line test.
$3.15 would be the cost, after the mark up is added.
Answer:please correct me if I’m wrong but I believe Part A for the slopes are…
1.3/1 or 3
2.-3
3.9/5
4.4/3
Step-by-step explanation:
It’s going up 3 and “running” 1 and it’s positive since the line is going up.
Y2-y1. -16-2
————= ————=-18/6=-3
X2-x1. 8-2
You’re just finding the slope
Solve for it. If further explanation is needed please tell me.
Your problem is too spaced out too understand! Next time make sure he spacing is more understandable and readable! sorry
Looks like the given limit is

With some simple algebra, we can rewrite

then distribute the limit over the product,

The first limit is 0, since 1/3ⁿ is a positive, decreasing sequence. But before claiming the overall limit is also 0, we need to show that the second limit is also finite.
For the second limit, recall the definition of the constant, <em>e</em> :

To make our limit resemble this one more closely, make a substitution; replace 9/(<em>n</em> - 9) with 1/<em>m</em>, so that

From the relation 9<em>m</em> = <em>n</em> - 9, we see that <em>m</em> also approaches infinity as <em>n</em> approaches infinity. So, the second limit is rewritten as

Now we apply some more properties of multiplication and limits:

So, the overall limit is indeed 0:
