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schepotkina [342]
3 years ago
10

The water level in a plastic pool changed by -8gallons each hour due to a small hole in the bottom. After 6 hours, the pool cont

ained 132 gallons. How much water was in the pool originally?
Mathematics
1 answer:
exis [7]3 years ago
5 0
You can find this using the equation x = 132 + (8)(6), where x is how much water was in the pool originally.

x = 132 + (8)(6)   Multiply
x = 132 + 48       Add
x = 180

There were originally 180 gallons of water in the pool.
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