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Charra [1.4K]
3 years ago
10

Let f(x)=cos(arctanx). What is the range of f?

Mathematics
1 answer:
Alenkasestr [34]3 years ago
4 0
-π/2 < arctan(x) < π/2

So cos(π/2) < cos(arctan(x)) < cos(0)

0 < cos(arctan(x)) < 1
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