Question

Right isosceles ΔA B C has hypotenuse length h . DE is a midsegment with length 4 x that is not parallel to the hypotenuse. What is the perimeter of ΔA B C ?

Answer 1

The perimeter of right isosceles ΔABC with midsegment DE is 16 + 8√2.

If right isosceles ΔABC has hypotenuse length h, then the two other sides are congruent.

side a = side b

Using Pythagorean theorem, c^2 = a^2 + b^2

h^2 = a^2 + b^2      a = b

h^2 = 2a^2

a = h/√2

If DE is a midsegment not parallel to the hypotenuse, then it is a segment that connects the midpoints of one side of a triangle and the hypotenuse. See photo for reference.

ΔABC and ΔADE are similar triangles.

a : b : h = a/2 : 4 : h/2

If a/2 = a/2, then b/2 = 4.

b/2 = 4

b = 8

If a = b, then a = 8.

If a = h/√2, then

8 = h/√2

h = 8√2

Solving for the perimeter,

P = a + b + h

P = 8 + 8 + 8√2

P = 16 + 8√2

P = 27.3137085

To learn more about midsegment: brainly.com/question/7423948

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