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BartSMP [9]
3 years ago
5

The answer is b I got it correct

Mathematics
1 answer:
Schach [20]3 years ago
5 0
Ok goodjob lol aaaaaaaaa
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Car A leaves San Diego at noon driving at 60 mph along a route which is 400 miles long to San Francisco. Car B leaves San Franci
lilavasa [31]
Distance = speed x time
Distance travelled by car A when car B started = 60 x 2 = 120 miles
Number of miles remaining at the time car B started = 400 - 120 = 280 miles.

At time of their meeting both cars has travelled a combined distance of 280 miles and has spent the same time.
Let t be the time they travelled together before they meet, then the sum of the distance travelled by car A and car B is 280miles.
60t + 80t = 280
140t = 280
t = 280/140 = 2 hours

After 2 hours car A has travelled a further 60 x 2 = 120 miles and car B has travelled 80 x 2 = 160 miles.

Total distance travelled be car A is 120 + 120 = 240 miles

Midpoint of the journey = 400/2 = 200 miles
Therefre, at the time they met, the were 40 miles from the midpoint and they are close to San Francisco.
3 0
3 years ago
Mr. Davis bought solar lights for a pathway at his house. The lights cost $29.95 each and have an
tamaranim1 [39]
You can set it up as an equation:

29.95x + 2x

then plug in x = 7.

I'm not sure how this really relates to the distributive property though.
6 0
3 years ago
10.
hichkok12 [17]
3. Anytime it asks you to find the parallel line it’s always the number attached to x
7 0
3 years ago
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Change 0.150 to a fraction.
Svetlanka [38]

Step-by-step explanation:

150/1000 and then you you have to simplify it

4 0
3 years ago
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∆ABC transforms to produce ∆A'B'C'. Which transformation did NOT take place?
never [62]

Answer: The answer is (D) Reflection across the line y = -x.


Step-by-step explanation:  In figure given in the question, we can see two triangles, ΔABC and ΔA'B'C' where the second triangle is the result of transformation from the first one.

(A) If we rotate ΔABC 180° counterclockwise about the origin, then the image will coincide with ΔA'B'C'. So, this transformation can take place here.

(B) If we reflect ΔABC across the origin, then also the image will coincide with ΔA'B'C' and so this transformation can also take place.

(C) If we rotate ΔABC through 180° clockwise about the origin, the we will see the image will be same as ΔA'B'C'. Hence, this transformation can also take place.

(D) Finally, if we reflect ΔABC across the line y = -x, the the image formed will be different from ΔA'B'C', in fact, it is ΔA'D'E', as shown in the attached figure. So, this transformation can not take place here.

Thus, the correct option is (D).


6 0
3 years ago
Read 2 more answers
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