What is the question? If you are only trying to expand the
expression then the answer would be:
1/4 (5y-3)+ 1/16 (12y+17)
(5y/4) – (3/4) + (12y/16) + (17/16)
1.25y – 0.75 + 0.75y + 1.0625
2y + 0.3125
If you are trying to find for y, then you forgot to equate
it to 0, that is:
2y + 0.3125 = 0
2y = -0.3125
<span>y = 0.15625</span>
so we have a table of values, with x,y coordinates, so let's use any two of those points to get the slope of the table and use the point-slope form to get its equation
![~\hspace{2.7em}\stackrel{\textit{let's use}}{\downarrow }\qquad \stackrel{\textit{and this}}{\downarrow }\\\begin{array}{|lr|r|r|r|r|}\cline{1-6}x&0&1&2&3&4\\y&-1&3&7&11&15\\\cline{1-6}\end{array}\\\\[-0.35em]\rule{34em}{0.25pt}\\\\(\stackrel{x_1}{1}~,~\stackrel{y_1}{3})\qquad(\stackrel{x_2}{4}~,~\stackrel{y_2}{15})](https://tex.z-dn.net/?f=~%5Chspace%7B2.7em%7D%5Cstackrel%7B%5Ctextit%7Blet%27s%20use%7D%7D%7B%5Cdownarrow%20%7D%5Cqquad%20%5Cstackrel%7B%5Ctextit%7Band%20this%7D%7D%7B%5Cdownarrow%20%7D%5C%5C%5Cbegin%7Barray%7D%7B%7Clr%7Cr%7Cr%7Cr%7Cr%7C%7D%5Ccline%7B1-6%7Dx%260%261%262%263%264%5C%5Cy%26-1%263%267%2611%2615%5C%5C%5Ccline%7B1-6%7D%5Cend%7Barray%7D%5C%5C%5C%5C%5B-0.35em%5D%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%28%5Cstackrel%7Bx_1%7D%7B1%7D~%2C~%5Cstackrel%7By_1%7D%7B3%7D%29%5Cqquad%28%5Cstackrel%7Bx_2%7D%7B4%7D~%2C~%5Cstackrel%7By_2%7D%7B15%7D%29)
Answer:
1. ΔXYZ is a right Δ with altitude YU.
Given
2. ΔXYZ ~ ΔYUZ
Right Triangle Altitude Similarity Theorem
3. VW || XY
Given
4. ∠VWZ ≅ ∠XYZ
Corresponding angles
5. ∠Z ≅ ∠Z
Reflexive property of congruence
6. ΔXYZ ~ ΔVWZ
AA Similarity postulate
7. ΔYUZ ~ ΔVWZ
Transitive property of similar triangles
Step-by-step explanation:
The first statement is given in the problem. Since we know the altitude of a right triangle, we can use the Right Triangle Altitude Similarity Theorem to say that the triangles formed by the altitude are similar to each other and the original triangle.
Next, we are given in the problem statement that the lines VW and XY are parallel. Therefore, ∠VWZ and ∠XYZ are corresponding angles, which makes them congruent. And since ∠Z is equal to itself (by reflexive property), we can use AA similarity to say ΔXYZ and ΔVWZ are similar.
Finally, combining statements 2 and 6, we can use transitive property to say that ΔYUZ and ΔVWZ are similar.
Answer:
full question
Step-by-step explanation:
full question
