Answer:
The quantity of water in the tank after 15 days is 1610.0 gallons OR 1.61 × 10³ gallons.
Step-by-step explanation:
The amount of water in the tank after 15 days is given by the series
910+(−710)+810+(−610)+⋯+310+(−110)+210
From the series, we can observe that, if water is added for a particular day then water will be drained the following day.
Also, for a day when water is to be added, the quantity to be added will be 100 gallon lesser than the quantity that was last added. Likewise, for a day when water is to be drained, the quantity to be drained will be 100 gallons lesser than the quantity that was last drained.
Hence, we can complete the series thus:
910+(−710)+810+(−610)+710(-510)+610(-410)+510(-310)+410(-210)+310+(−110)+210
To evaluate this, we get
910-710+810-610+710-510+610-410+510-310+410-210+310-110+210
= 1610.0 gallons
Hence, the quantity of water in the tank after 15 days is 1610 gallons OR 1.61 × 10³ gallons.
If a set of exam scores forms a symmetrical distribution, then the student mean scores is the median and the mode too.
<h3>What is a Symmetrical distribution?</h3>
A symmetrical distribution by definition is the situation which occurs when the values of variables appear at regular frequencies and is characterized by the mean, median, and mode all occuring at the same point in most cases.
Graphically, symmetrical distributions may appear as a normal distribution (i.e., bell curve).
Read more on Symmetrical distribution;
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