Answer:
Step-by-step explanation:
f"(x)=2
integrating
f'(x)=2x+c
f'(1)=2+c=4
c=4-2=2
f'(x)=2x+2
integrating
f(x)=2x^2/2+2x+a
f(x)=x^2+2x+a
f(2)=-2
(2)^2+2(2)+a=-2
4+4+a=-2
a=-2-8=-10
f(x)=x^2+2x-10
Answer:
Yes they are.
Because:
As said in the rules you have to keep the bases and add the exponents.
We do like the following:
Set the first number is a and the second is b.
We have two equations: a+2xb=24, 2xa+b=21
And we have 2xa+4xb=48 or 2xa=48-4xb
So: 48-4xb+b=21 or -3xb=21-48=-27 and we got b=-27:(-3)=9 and a= 6
a=6 and b=9
Answer:
3.777
Step-by-step explanation:
