Answer:
4(3n+2) or 12n+8
Step-by-step explanation:
Given expression is:
The numerator of the fraction will be multiplied with 9n^2- 4
So, Multiplication will give us:
We can simplify the expression before multiplication.
The numerator will be broken down using the formula:
![a^2 - b^2 = (a+b)(a-b)\\So,\\= \frac{8[(3n)^2 - (2)^2]}{6n-4}\\ = \frac{8(3n-2)(3n+2)}{6n-4}](https://tex.z-dn.net/?f=a%5E2%20-%20b%5E2%20%3D%20%28a%2Bb%29%28a-b%29%5C%5CSo%2C%5C%5C%3D%20%5Cfrac%7B8%5B%283n%29%5E2%20-%20%282%29%5E2%5D%7D%7B6n-4%7D%5C%5C%20%3D%20%5Cfrac%7B8%283n-2%29%283n%2B2%29%7D%7B6n-4%7D)
We can take 2 as common factor from denominator
Hence the product is 4(3n+2) or 12n+8 ..
4.0081 x 10 to the 4th power. I know because I did this one.
Answer:
a. x = 2 , x = -5
b. no real roots
Step-by-step explanation:
<u>a. x² + 3x – 10</u>
= x² - 2x + 5x - 10
= x (x²/x - 2x/x) + 5 (5x/5 - 2*5/5)
= (x - 2) (x + 5)
x - 2 = 0 x + 5 = 0
+ 2 +2 -5 -5
-------------- ---------------
x = 2 x = -5
x = 2 , x = -5
<u>b. 2x² - 4x + 3 </u>
This can't be solved because the equation has no real roots, and also the discriminant is negative.
Answer:
∠EGF = 1/2( 180 - 50) = 1/2(130) = 65
∠CGF = 180 - 65 = 115.
Step-by-step explanation:
Step-by-step explanation:
We can prove the statement is false by proof of contradiction:
We know that cos0° = 1 and cos90° = 0.
Let A = 0° and B = 90°.
Left-Hand Side:
cos(A + B) = cos(0° + 90°) = cos90° = 0.
Right-Hand Side:
cos(A) + cos(B) = cos(0°) + cos(90°)
= 1 + 0 = 1.
Since LHS =/= RHS, by proof of contradiction,
the statement is false.
