Write the equation of a line through points (5,5) and (1,0) in point-intercept form.

Mathematics

1 answer:

Sati [7]3 years ago

7 0

Answer:

The slope-intercept form is y = 5/4x - 5/4 and the point-slope form is y - 0 = 5/4(x - 1)

Step-by-step explanation:

There is no such thing as point-intercept form. There is point-slope form and slope-intercept form. To find either of those, you can follow the steps below.

First find the slope of the equation using the slope formula.

m(slope) = (y2 - y1)/(x2 - x1)

m = (5 - 0)/(5 - 1)

m = 5/4

Now we can use the slope along with a point to get the point-slope form.

y - y1 = m(x - x1)

y - 0 = 5/4(x - 1) ------->THIS IS POINT-SLOPE

Now to get slope-intercept, solve for y

y - 0 = 5/4(x - 1)

y = 5/4x - 5/4

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What is the relationship between exponentials and logarithms? How can you use these to solve equations? Provide an example in yo

Sveta_85 [38]

Answer:

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Step-by-step explanation:

Exponentials and logarithms are inverses of each other.

For logarithmic function:

Domain = $\left ( 0,\infty \right )$ , Range = $\left ( -\infty ,\infty \right )$

Vertical asymptote is y - axis.

x - intercept is (1,0)

For exponential function:

Domain = $\left ( -\infty ,\infty \right )$ , Range = $\left ( 0,\infty \right )$

Horizontal asymptote is x - axis.

y- intercept is (0,1)

Both exponential and logarithmic functions are increasing.

For example:

Solve: $\log x=\frac{\log 5+\log 3}{\log 3^2}$

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