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lara31 [8.8K]
4 years ago
15

A 6 ft vertical pole casts a 14 in shadow at the same time a nearby cell phone tower casts a 119 ft shadow how tall is the cell

phone tower
Mathematics
1 answer:
o-na [289]4 years ago
7 0
The tower is 612 feet. to solve this you have to convert the 6ft from into inches which is 72in then divide youll get 5.14285714 then times it by 119ft. because its about ratio.
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Stacy wants to build a patio with a small, circular pond in her backyard.The pond will have a 6-foot radius. She also wants to i
Komok [63]
We know that

step 1
the area to install tiles is equal to A
A=area rectangle-area of a circle

area of a rectangle=(13+x)*x-----> (13x+x²) ft²

area of a circle=pi*r²-----> pi*6²------> 36*pi ft²
A=(x²+13x)-36*pi  ft²

step 2
find the cost of installing tiles CT
CT=$1*[(x²+13x)-36*pi]-----> CT=$x²+$13x-$36*pi

step 3
find the cost <span>the of installing the pond CP
CP=$0.62*36*pi------> CP$22.32*pi

step 4
find the inequality
we know that
CT+CP </span>\leq<span> $536
[</span>$x²+$13x-$36*pi]+[$22.32*pi]  \leq $536

[$x²+$13x-$13.68*pi]  \leq $536

the answer is the option D
4 0
4 years ago
Read 2 more answers
What is the equation of the line that goes through (3,11) and is parallel to the line 2x-y=5
Strike441 [17]
The equation is y=2x+5
why?
2x-y=5
y=2x-5
from here we can find the slope, which is 2, and we know that parallel lines have equal slopes
 the standard form of eq of line is y=mx+b
substitute y and x with the numbers from ordinate pair (3,11):
11=3*2+b
6+b=11
b=5
Now you can write the eq of line:
y=2x+5
3 0
4 years ago
Factor the polynomial. x3 - 4x2 - 6x + 24
ladessa [460]
If the 4x2 is actually 4x^2 then the answer is 

-(4x+3x-24)
4 0
3 years ago
Read 2 more answers
Find the perimeter and area of the polygon with the given vertices E(6,-2), F(6,5), G(-1,5)
kaheart [24]

Answer:  Perimeter ≈ 23.9       Area = 24.5

<u>Step-by-step explanation:</u>

Perimeter is the sum of the sides.

EF = 7

FG = 7

EG = 7√2

Perimeter = EF + FG + EG

                 = 7  +  7  + 7√2

                 =      14    + 7√2

                 ≈          23.9

Area = \dfrac{1}{2}(base x height)

        =\dfrac{1}{2}(7 x 7)

        = \dfrac{49}{2}

        = 24.5

6 0
3 years ago
This figure is made up of a quadrilateral and a semicircle.
Arturiano [62]

Answer:

The correct option is B. The area of the figure is 40.4 units².

Step-by-step explanation:

The line AB divides the figure in two parts one is a rectangle and another is semicircle.

The distance formula is

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

The length of AB is

AB=\sqrt{(2+3)^2+(4-2)^2}=\sqrt{25+4}=\sqrt{29}

The length of AD is

AD=\sqrt{(-1+3)^2+(-3-2)^2}=\sqrt{4+25}=\sqrt{29}

Since AB=AD, therefore ABCD is a square. The area of the of square is

A_1=a\times a=\sqrt{29}\times \sqrt{29} =29

The area of square is 29 units².

The area of a semicircle is

A_2=\frac{\pi}{2}r^2

Since AB is the diameter of the semicircle, therefore the radius of the semicircle is

r=\frac{d}{2}=\frac{\sqrt{29}}{2}

The area of the semicircle is

A_2=\frac{3.14}{2}(\frac{\sqrt{29}}{2})^2=40.3825

The area of the figure is

A=A_1+A_2=29+11.2825=40.3825\approx 40.4

Therefore the area of the figure is 40.4 units². Option B is correct.

5 0
4 years ago
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