The large hose fills 1 pool in 9 hours written as 1/9
The small hose fills 1 pool in 18 hours, written as 1/18
Now you have 1/9 + 1/18 = 1/x ( x is the unknown time for both hoses).
rewrite 1/9 with a common denominator as 1/18:
1/9 = 2/18
Now you have 2/18 + 1/18 = 1/x
Add the left side:
2/18 + 1/18 = 3/18
Now you have 3/18 = 1/x
Cross Multiply:
3x = 18
Divide both sides by 3"
x = 18/3
X = 6
It will take both hoses 6 hours.
Answer: A. 31.5
Step-by-step explanation:
Using law of cosine because it is side angle side
a=16
b=21
angle = 116
c^2=a^2+b^2-2ab cosC, let C be the angle given
c^2=(21)^2+(16)^2-2(16)(21) cos(116)
c^2=441+256-672 cos(116)
i used a ti-89 and answered the right side and got
(you can find a ti-89 simulator online, but for problems like this make sure it is in degree mode)
991.585
c^2=991.585
take square root of both sides
=31.4894, which if you round it up it would be 31.5, so the answer would be A
therefore:
a=16
b=21
c=31.5
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Answer:
Its the first choice: right, scalene.
Step-by-step explanation:
It is a right angled triangle, (indicated by the little square at Q).
The sides have different lengths so it scalene.
Answer:
Ques 16)
We have to simplify the expression:
Ques 17)
Ques 18)
Let the blank space be denoted by the quantity 'x'.
Ques 19)
Let the missing quantity be denoted by 'x'.
