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ioda
3 years ago
9

Solve for 2x² + x = 10 *show your work

Mathematics
1 answer:
AleksAgata [21]3 years ago
6 0

Answer:

(2x + 5) (x - 2)

Step-by-step explanation:

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PLEASE HELP!!!<br> Fill in the blanks problem<br> (please view both attachments)
WINSTONCH [101]

angle 5 = angle 1 = Corresponding Angles Postulate

angle 6 + angle 5 = 180 =  linear pair postulate

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3 years ago
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Answer choices<br> A. 23<br> B. 25<br> C. 35<br> D. 50
Tasya [4]
35? I’m not sure what the question is asking
3 0
3 years ago
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Plz help due tommorow big grade
Korvikt [17]
It would take 4750 because 1L is 5000 ml and 5000-250=4750. Use the web to do it in metric measurements.
3 0
3 years ago
What is the product?
fredd [130]

Answer:

\frac{4k + 2}{k^{2}-4 }  ×  \frac{k-2}{2k+1}   =  \frac{2}{k + 2}

Step-by-step explanation:

\frac{4k + 2}{k^{2}-4 }  ×  \frac{k-2}{2k+1}

To solve the above, we need to follow the steps below;

4k+2 can be factorize, so that;

4k +2 = 2 (2k + 1)

k² - 4  can also be be expanded, so that;

k² - 4 = (k-2)(k+2)

Lets replace  4k +2  by  2 (2k + 1)

and

k² - 4 by  (k-2)(k+2)   in the expression  given

\frac{4k + 2}{k^{2}-4 }  ×  \frac{k-2}{2k+1}

\frac{2(2k+ 1)}{(k-2)(k+2)}   ×  \frac{k-2}{2k+1}

(2k+1) at the numerator will cancel-out (2k+1) at the denominator, also (k-2) at the numerator will cancel-out (k-2) at the denominator,

So our expression becomes;  

\frac{2}{k + 2}

Therefore, \frac{4k + 2}{k^{2}-4 }  ×  \frac{k-2}{2k+1}   =  \frac{2}{k + 2}

3 0
3 years ago
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Is 12n2+12n+1 prime over the set of polynomials with rational coefficients? Need help ASAP
professor190 [17]

Answer:

No, the given polynomial is not prime.

Step-by-step explanation:

Given: a polynomial 12n^2+12n+1

To check: whether the given polynomial is prime or not.

Solution:

A prime polynomial is a polynomial that cannot be factored into polynomials of lower degree and has integers as coefficients.

In the given polynomial, coefficients are integers.

Also, the polynomial 12n^2+12n+1 cannot be factored further into polynomials of lower degree.

So, the given polynomial is not prime.

8 0
3 years ago
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