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3 years ago

How do economists measure a nation's standard of living

Mathematics

1 answer:

castortr0y [4]3 years ago

7 0

Answer:

A was not correct for Plato

Step-by-step explanation:

A. by calculating GDP per person - Not correct on Plato

B. by calculating per capita income

C. by calculating average personal income

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PLZ HELP!!!!

lozanna [386]

Answer:

(Q) Find the amount in the account at the end of 1 year.

(A) $8,190

(Q) Find the amount in the account at the end of 2 years.

(A) $16,380

4 0

3 years ago

You have 3434 of a pie leftover after your party. Each guest takes home 1616 of the leftover pie.

Pachacha [2.7K]

You would have 1818 of pie left over...... I do not know the fraction of it

7 0

3 years ago

Read 2 more answers

13. After Valentine's Day, boxes of chocolates go on sale and are marked down 10%. The

Anna007 [38]

Answer:

$27.00

Step-by-step explanation:

First, 10% of 30 = 3.

Second, 30 - 3 = 27

Hope this helps!

5 0

3 years ago

4(2x - 5) + 15 = 11 Write the steps you will use to solve the equation and explain each step.

vagabundo [1.1K]

First, multiply 4*2x-4*-5= 8x-20.
Second, add 15 to 8x-20
Third, that would equal 8x-20+15=11
Fourth, 15+-20= -5
Fifth, 8x-5=11
Sixth, add +5 to -5 and +5 to 11= 8x=16
Last, do 8x/8x and 16/8x
The answer is x=2

6 0

3 years ago

Read 2 more answers

The weights of 67 randomly selected axles were found to have a variance of 3.85. Construct the 80% confidence interval for the p

VLD [36.1K]

Answer:

$3.13$

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 67

Variance = 3.85

We have to find 80% confidence interval for the population variance of the weights.

Degree of freedom = 67 - 1 = 66

Level of significance = 0.2

Chi square critical value for lower tail =

$\chi^2_{1-\frac{\alpha}{2}}= 51.770$

Chi square critical value for upper tail =

$\chi^2_{\frac{\alpha}{2}}= 81.085$

80% confidence interval:

$\dfrac{(n-1)S^2}{\chi^2_{\frac{\alpha}{2}}} < \sigma^2 < \dfrac{(n-1)S^2}{\chi^2_{1-\frac{\alpha}{2}}}$

Putting values, we get,

$=\dfrac{(67-1)3.85}{81.085} < \sigma^2 < \dfrac{(67-1)3.85}{51.770}\\\\=3.13$

Thus, (3.13,4.91) is the required 80% confidence interval for the population variance of the weights.

8 0

3 years ago