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3 years ago

PLEASE HELP!!

Mathematics

1 answer:

joja [24]3 years ago

8 0

Answer:

Third one I believe

Step-by-step explanation:

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F(x)=2x an$ g(x)=2x+3,what is the value of f(g(-8))

Fudgin [204]

First plug in g(x) into f(x)

F((g(x))=2(2x+3)

And now you plug in -8

F(g(-8))=2(-16+3)

F(g(-8))=2(-13)

F(g(-8))=-26

6 0

3 years ago

15 points and BRAINLIEST John and his sister each bought a car in 2005. John's car cost $3,000 and is decreasing in value $150 p

nignag [31]

Answer:

Step-by-step explanation:

5 0

3 years ago

Suppose that 21 out of 25 people who apply to a certain college are accepted. What percentage of people who apply are accepted t

IgorC [24]

Answer:

84%

Step-by-step explanation:

The first step is to write 21 as a fraction of 25, which is simply

21/25

Now we just need to convert this fraction to a percentage :

21/25 = 84

So, 21 is 84% of 25

8 0

3 years ago

The diameters of ball bearings are distributed normally. The mean diameter is 83 millimeters and the standard deviation is 3 mil

Alenkinab [10]

Answer:

0.2514 = 25.14% probability that the diameter of a selected bearing is greater than 85 millimeters.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

$\mu = 83, \sigma = 3$

Find the probability that the diameter of a selected bearing is greater than 85 millimeters.

This is 1 subtracted by the pvalue of Z when X = 85. Then

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{85 - 83}{3}$

$Z = 0.67$

$Z = 0.67$ has a pvalue of 0.7486.

1 - 0.7486 = 0.2514

0.2514 = 25.14% probability that the diameter of a selected bearing is greater than 85 millimeters.

7 0

3 years ago

The expression cosine of pi over 2 times cosine of pi over 3 plus sine of pi over 2 times sine of pi over 3 can be rewritten as

9966 [12]

Solution:

Given;

$\cos\frac{\pi}{2}\cos\frac{\pi}{3}+\sin\frac{\pi}{2}\sin\frac{\pi}{3}$

Using the identities;

Thus;

$\begin{gathered} \cos\frac{\pi}{2}\cos\frac{\pi}{3}+\sin\frac{\pi}{2}\sin\frac{\pi}{3}=\cos(\frac{\pi}{2}-\frac{\pi}{3}) \\ \\ \cos\frac{\pi}{2}\cos\frac{\pi}{3}+\sin\frac{\pi}{2}\sin\frac{\pi}{3}=\cos(\frac{\pi}{6}) \end{gathered}$

CORRECT OPTION: A

6 0

1 year ago