<h3>
Answer:</h3>
1/17 or 0.0588 (without replacement)
<h3>
Step-by-step explanation:</h3>
To answer this question we need to know the following about a deck of cards
- A deck of cards contains 4 of each card (4 Aces, 4 Kings, 4 Queens, etc.)
- Also there are 4 suits (Clubs, Hearts, Diamonds, and Spades).
- Additionally, there are 13 cards in each suit (Clubs/Spades are black, Hearts/Diamonds are red)
.
In this case, we are required to determine the probability of choosing two diamonds.
- There are 13 diamonds in the deck.
- Assuming, the cards were chosen without replacement;
P(Both cards are diamonds) = P(first card is diamond) × P(second card is diamond)
P(First card is diamond) = 13/52
If there was no replacement, then after picking the first diamond card, there are 12 diamond cards remaining and a total of 51 cards remaining in the deck.
Therefore;
P(Second card is diamond) = 12/51
Thus;
P(Both cards are diamonds) = 13/52 × 12/51
= 156/2652
= 1/17 or 0.0588
Hence, the probability of choosing two diamonds at random (without replacement) is 1/17 or 0.0588.
Answer:
Step-by-step explanation:
3x + 2 + 58 = 90
3x + 60 = 90
3x = 30
x = 10
it's adjacent
Answer:
27
27 - 2 is 25, and 16 + 9 = 25
Answer:
630 minutes.
Step-by-step explanation:
That would be the lowest common multiple of 10, 14 and 18
10 = 2 x 5
14= 2 x 7
18 = 2 x 3 x 3
The LCM = 2 x 3 x 3 x 5 x 7
= 630.
Answer:18224
Step-by-step explanation:
