15 points and BRAINLIEST John and his sister each bought a car in 2005. John's car cost $3,000 and is decreasing in value $150 p
er year. The value () of his sister's car x years after 2005 is given by
the function V(x) = 250x + 4,000. Which statement correctly compares the values of the cars from 2005 until 2017?
the function V(x) = 250x + 4,000. Which statement correctly compares the values of the cars from 2005 until 2017?
1 answer:
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Answer:
$ 1,060.00
Step-by-step explanation:
A = $ 1,060.00
A = P + I where
P (principal) = $ 1,000.00
I (interest) = $ 60.00
Compound Interest Equation
A = P(1 + r/n)^nt
Where:
A = Accrued Amount (principal + interest)
P = Principal Amount
I = Interest Amount
R = Annual Nominal Interest Rate in percent
r = Annual Nominal Interest Rate as a decimal
r = R/100
t = Time Involved in years, 0.5 years is calculated as 6 months, etc.
n = number of compounding periods per unit t; at the END of each period
Step-by-step explanation:
Hey, there!!
Given that,
{ we can write (a^2-4) as (a^2 - 2^2) also as (x^2- 9) can be written as (x^2 - 3^2)}.
We have a^2-b^2= (a+b) (a-b), so keep same formula on it.
(x+3) in numerator and denominator gets cancelled,
Therefore, (x-3) is the final value.
<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>