Answer:
decrease by 50%
Step-by-step explanation:
Decreased by 60% = (100%-60%)x = 0.4x.
Decreased by 20% = (100%-20%)x = 0.8x.
initial fraction, and we can see that denominator will increase 2 times, so fraction will decrease 2 times, or decrease by 50%.
Answer:

Step-by-step explanation:
Since there are 20 students, this will be the denominator.
Now, to find how many students have a dog and a cat, you need to subtract all the numbers with 20. The leftover number will be the amount of students.
7+8+8=23
23-20=3
So, there are 3 students who have a dog and a cat.
So, the fraction will be 
<u><em>Answer:</em></u>
c
−
135
<u><em>Explanation:
</em></u>
Let's say that the amount of money in Bailey's checking account is
c dollars.
We also know that she took away $
135
From this variable and number, we can state the algebraic expression
c
−
135
<h2><u><em>
Hope this helps!</em></u></h2>
<u><em></em></u>
Answer:
- P(t) = 100·2.3^t
- 529 after 2 hours
- 441 per hour, rate of growth at 2 hours
- 5.5 hours to reach 10,000
Step-by-step explanation:
It often works well to write an exponential expression as ...
value = (initial value)×(growth factor)^(t/(growth period))
(a) Here, the growth factor for the bacteria is given as 230/100 = 2.3 in a period of 1 hour. The initial number is 100, so we can write the pupulation function as ...
P(t) = 100·2.3^t
__
(b) P(2) = 100·2.3^2 = 529 . . . number after 2 hours
__
(c) P'(t) = ln(2.3)P(t) ≈ 83.2909·2.3^t
P'(2) = 83.2909·2.3^2 ≈ 441 . . . bacteria per hour
__
(d) We want to find t such that ...
P(t) = 10000
100·2.3^t = 10000 . . . substitute for P(t)
2.3^t = 100 . . . . . . . . divide by 100
t·log(2.3) = log(100)
t = 2/log(2.3) ≈ 5.5 . . . hours until the population reaches 10,000
Answer:
I think it is 730
Step-by-step explanation:
I hope this helped o(〃^▽^〃)o