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2 years ago

9

Can someone help me

2 answers:

marysya [2.9K]2 years ago

8 0

Answer:

I think it is the first one ( 2,0)

but if I am wrong I am sorry

sukhopar [10]2 years ago

3 0

Hello there!

The answer is number one or circle one. Because B is right on top of it. Meaning that it's just one whole number and in this case would be 2.

I hope this helps

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the line for the dunking machine was twice as long as the cake walk line the line for the Cakewalk was one third of the length o

Amanda [17]

Answer:

Total number of people in the line for the dunking machine is 8.

Step-by-step explanation:

Here, let us assume the number of people in the line for hoop shoot = 12

So, the number of people in the line for cakewalk

= One- Third of the number of people in line for Hoop Shoot

= $\frac{1}{3} \times 12 = 4$

Also, the number of people in the line for dunking machine

= 2 x ( The number of people in line for Cakewalk)

= 2 x 4 = 8

Hence, the total number of people in line for the dunking machine is 8.

3 0

3 years ago

Write an equation in slope-intercept form of<br> the line that passes through (-6,4) and<br> (-1,2).

xz_007 [3.2K]

Answer:

Step-by-step explanation:

(-6 , 4) & (-1 , 2)

Slope = $\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

$= \frac{2-4}{-1-[-6]}\\\\= \frac{-2}{-1+6}\\\\= \frac{-2}{5}$

m = -2/5 & (-6 , 4)

y -y1 = m(x -x1)

$y - 4 = \frac{-2}{5}(x - [-6])\\\\y - 4 = \frac{-2}{5}(x + 6)\\\\y - 4 = \frac{-2}{5}x + 6*\frac{-2}{5}\\\\y = \frac{-2}{5}x -\frac{12}{5}+4\\\\y=\frac{-2}{5}x-\frac{12}{5}+\frac{4*5}{1*5}\\\\y=\frac{-2}{5}x-\frac{12}{5}+\frac{20}{5}\\\\y=\frac{-2}{5}x+\frac{8}{5}$

6 0

3 years ago

PLEASE HELP ME!!!! I NEED THIS QUICKLY!!

zloy xaker [14]

Part A: $y=-\frac{5}{4} x+\frac{35}{2}$ is the equation of the line.

Part B: Anika worked 17.5 hours on day 0.

Part C: The setup time decreases with 1 hour and 15 min per day.

Explanation:

Part A: Let us find the equation of the line using the points (2,15) and (6,10)

The equation of the line is given by,

$y-y_{1}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \cdot\left(x-x_{1}\right)$

Substituting, we get,

$y-15=\frac{10-15}{6-2} (x-2)$

Simplifying, we have,

$y-15=-\frac{5}{4} (x-2)$

$y-15=-\frac{5}{4} x+\frac{5}{2}$

Subtracting both sides by 15, we get,

$y=-\frac{5}{4} x+\frac{35}{2}$

Hence, the equation of the line is $y=-\frac{5}{4} x+\frac{35}{2}$

Part B: To determine the number of hours Anika worked on day 0, let us substitute x = 0 in the equation of the line.

Thus, we get,

$y=\frac{35}{2}\\y=17.5$

Hence, Anika worked 17.5 hours on day 0.

Part C: The setup time decrease per day can be determined using the slope.

The formula for slope is given by

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Substituting , we have,

$m=\frac{10-15}{6-2}=-\frac{5}{4}$

Converting the fraction into hours and minutes, we get,

$-\frac{5}{4}\times60=-75 min$

Since, 1 hour = 60 min

Subtracting 60 and 75 = 15 min

Thus, the setup time decreases with 1 hour and 15 min per day.

6 0

3 years ago

Its all one big question

Verdich [7]

Answer:

see explanation

Step-by-step explanation:

h(x) + k(x) = x² + 1 + x - 2 = x² + x - 1

(h + k)(2) = 2² + 2 - 1 = 4 + 2 - 1 = 5

h(x) - k(x) = x² + 1 - (x - 2) = x² + 1 - x + 2 = x² -x + 3

(h - k)(3) = 3² - 3 + 3 = 9 - 3 + 3 = 9

h(2) = 2² + 1 = 4 + 1 = 5

k(3) = 3 - 2 = 1

3h(2) + 2k(3) = (3 × 5) + (2 × 1) = 15 + 2 = 17

7 0

3 years ago

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By selling a laptop at $1,000 for which consumers are willing to pay up to $1,200, a consumer electronics firm makes a profit of

mr Goodwill [35]

Answer:

600

Step-by-step explanation:

7 0

3 years ago