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katovenus [111]
3 years ago
11

Write an equation of the ellipse centered at the origin given its vertex and co vertex

Mathematics
1 answer:
jolli1 [7]3 years ago
4 0

Answer:

\dfrac{x^2}{49}+\dfrac{y^2}{25}=1.

Step-by-step explanation:

The equation of the ellipse is

\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1.

If the vertex of the ellipse is at point (-7,0), then a=7.

If the co-vertex of the elllipse is at point (0,-5), then b=5.

The equation of the ellipse is

\dfrac{x^2}{7^2}+\dfrac{y^2}{5^2}=1,

\dfrac{x^2}{49}+\dfrac{y^2}{25}=1.

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What is the simplified form of the following expression? 2√27+√12-3√3-2√12
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Answer:

√3

Step-by-step explanation:

The given expression to be simplified is

2 \sqrt{27}+\sqrt{12}-3\sqrt{3}-2 \sqrt{12}

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\sqrt{12}=\sqrt{4\times3}= \sqrt{4}\times \sqrt{3}=2\sqrt{3}

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2\sqrt{12}=2\times2\sqrt{3}=4 \sqrt{3}

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2 \sqrt{27}+\sqrt{12}-3\sqrt{3}-2 \sqrt{12}=6\sqrt{3}+2\sqrt{3}-3 \sqrt{3} -4\sqrt{3}

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The simplified form of ,

2 \sqrt{27}+\sqrt{12}-3\sqrt{3}-2 \sqrt{12} is √3

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