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LuckyWell [14K]
3 years ago
12

The total number of pieces of cake left at a wedding is can be represented by P(t) = 350(0.8)t where t represents time in minute

s and 350 is the number of pieces of cake that the bride and groom started with when the wedding begins. What would the range be if we used the appropriate domain to find out how many pieces were left after 5, 10 and 15 minutes?
Mathematics
2 answers:
levacccp [35]3 years ago
6 0
I believe you meant 0.8^t. Then the number of pieces left would be:
t=5
350 (0.8)^5=114.7
t=10
350 (0.8)^10=37.6
t=15
350(0.8)^15=12.3
☺☺☺☺
olasank [31]3 years ago
5 0
I believe it is supposed to be (0.8^x) because if it was like it was written, ur cake would be getting bigger.
ur range is gonna be P(t) while ur domain is t
P(t) = 350(0.8)^t

after 5 minutes
P(5) = 350(0.8^5)
P(5) = 350(114.688)
P(5) = 115 pieces <==

after 10 minutes
P(10) = 350(0.8^10)
P(10) = 37.581
P(10) = 38 pieces <==

after 15 minutes
P(15) = 350(0.8^15)
P(15) = 12.315
P(15) = 12 pieces <==




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Step-by-step explanation:

Given as :

The Total money invested = $13,957

Let The money invested at 7% = p_1  = $A

And The money invested at 6% = p_2 = $13957 - $A

Let The interest earn at 7% = I_1

And The interest earn at 6% = I_2

I_1 -  I_2 = $833.73

Let The time period = 1 year

Now,<u> From Simple Interest method</u>

Simple Interest = \dfrac{\textrm principal\times \textrm rate\times \textrm time}{100}

Or,  I_1 = \dfrac{\textrm p_1\times \textrm 7\times \textrm 1}{100}

Or,  I_1 = \dfrac{\textrm A\times \textrm 7\times \textrm 1}{100}

And

I_2 = \dfrac{\textrm p_2\times \textrm 6\times \textrm 1}{100}

Or,  I_2 = \dfrac{\textrm (13,957 - A)\times \textrm 6\times \textrm 1}{100}

∵  I_1 -  I_2 = $833.73

So, \dfrac{\textrm A\times \textrm 7\times \textrm 1}{100} -  \dfrac{\textrm (13,957 - A)\times \textrm 6\times \textrm 1}{100} = $833.73

Or, 7 A - 6 (13,957 - A) = $833.73 × 100

Or, 7 A - $83,742 + 6 A = $83373

Or, 13 A = $83373 + $83742

Or, 13 A = $167,115

∴ A = \dfrac{167115}{13}

i.e A = $12,855

So, The Amount invested at 7% interest = A = $12,855

And The Amount invested at 6% interest = ($13,957 - A) = $13,957 - $12,855

I.e The Amount invested at 6% interest = $1,102

Hence,The Amount invested at 7% interest is $12,855

And The Amount invested at 6% interest = $1,102   . Answer

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Combine like terms.

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