Nonane because the molecule contains 9 carbon atoms without any side branches (Non-) and because it only contains single C-C bonds so it is an alkane (-ane).
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<span>There are a few ways that may cause me to forget the process of classical conditioning. First, I could be having retroactive interference. In this case, the newer information that I am just now learning about could be interfering with my retrieval of previous information. Second, I could be experiencing decay. This would mean that it’s been so long since I’ve learned about classical conditioning that my memory trace has not been used and I’ve started to forget about it. Finally, I also could simply have failed to process the memory in a process known as encoding failure. (One more option is that I am suffering from retrograde amnesia, but that is unlikely).</span>
Answer is a
*The correct answer is IJ = JK
•explanation:
Given:
AB is the perpendicular bisector of
IK. ⇒ AB divides the line segment IK in two equal parts i.e. IJ = JK and the angle formed at the point of intersection J is 90° ⇒ ∠AJI = 90°. In ΔAIJ, By angle sum property of a triangle ∠AJI + ∠AIJ + ∠IAJ = 180° ( But ∠AJI = 90° ) ∠AIJ + ∠IAJ = 90° ⇒ ∠IAJ < 90° So, ∠IAJ is not a right angle. Its not given IK is a perpendicular bisector so AJ = BJ need NOT be true. As A does not lie on the line IK so A can not be the mid point of IK.
•Hence, we conclude the correct statement is IJ = JK