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ASHA 777 [7]
3 years ago
10

Hi everybody.Who could help with my gw please:))But when u would write the answets please write thev

Mathematics
1 answer:
podryga [215]3 years ago
3 0
% error = {|Approximate Value - Exact Value| ÷ |Exact Value|} * 100%

The difference of the Approximate and the Exact Value is an absolute value. Therefore, the negative sign of the difference is disregarded.

1) Estimate = 250 g ; Actual = 240 g
(250 - 240)/240 * 100% = 10/240 * 100% = 4.17%

2) Estimate = 97.5°C ; Actual = 100°C
(97.5 - 100)/100 * 100% = |-2.5|/100 * 100/% = 2.5%

3) Estimate = 10.4 ml ; Actual = 9.7 ml
(10.4 - 9.7)/9.7 * 100% = 0.7/9.7 * 100% = 7.22%

4) Estimate = 0.156 cal/g°C ; Actual = 0.185 cal/g°C
(0.156-0.185)/0.185 * 100% = |-0.029|/0.185 * 100% = 15.68%

5) Estimate = 62.5 g ; Actual = 65.2 g
(62.50 - 65.20)/65.20 * 100% = |-2.7|/65.20 * 100% = 4.14%
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The otherSites Squared10.A cylinder has a diameter of 12 meters and a height of 9 meters. What is thetotal surface area of the c
Gelneren [198K]

The total surface area of a cylinder is given by the formula

\begin{gathered} A_{cylinder}=2circular\text{ area+curved surface area} \\ =2\pi r^2+2\pi rh \end{gathered}

Given diameter, d=12meters, we will solve for radius

\begin{gathered} \text{diameter,d}=2\times radius,r \\ d=2r \\ r=\frac{d}{2} \\ r=\frac{12m}{2} \\ r=6m \end{gathered}

The height is given as 9meters

Substituting for r and h in the formula will give

\begin{gathered} A_{cylinder}=2\pi r^2+2\pi rh \\ r=6m;h=9m;\pi=3.14 \\ A_{cylinder}=2\times3.14\times6^2+2\times3.14\times6\times9_{} \end{gathered}\begin{gathered} A_{cylinder}=6.28\times36+6.28\times54 \\ =226.08+339.12 \\ =565.2m^2 \end{gathered}

Hence the surface area of the cylinder is 565.2m²

8 0
9 months ago
g In 2013, the Pew Research Foundation reported that 43% of U.S. adults report that they live with one or more chronic condition
SOVA2 [1]

Answer:

We are 95% confident that the true proportion of U.S. adults who live with one or more chronic conditions is between 39.7% and 46.33%

Step-by-step explanation:

From the question we are told that

  The  sample  proportion is \r p = 43\%  = 0.43

   The  standard error is SE =  0.017

Given that the confidence level is 95%  then the level of significance is mathematically represented as  

      \alpha =  (100-95)\%

=>   \alpha = 0.05

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.96

Generally the margin of error is mathematically represented as

     E = Z_{\frac{\alpha }{2} } *  SE

=>    E = 1.96 *  0.017

=>     E = 0.03332

Generally 95% confidence interval is mathematically represented as

      \r p -E <  p <  \r p +E

=>   0.43 -0.03332 <  p <  0.43 + 0.03332

=>    0.39668 <  p <  0.46332

Converting to percentage

(0.39668 * 100)<  p <  (0.46332*100)        

39.7\% <  p < 46.33 \%    

7 0
3 years ago
Which of the numbers below could be terms in the sequence an=4n-7 A)29 B)21 C)20 D)28
natali 33 [55]

Answer:

A)29 and B) 21,

Step-by-step explanation:

First,in the sequencea_n=4n-7 , the parameter n must to be a integer.

Second, we need to solve the equations by  n.

n=(a_n+7)/4

All the option in the problem represent an a_n

Then, we need to prove all number in the options, if the result is a integer number, this option can be part of the sequence.

For A)

n=(29+7)/4=9\\

For B)

n=(21+7)/4=7\\

For C)

n=(20+7)/4=6.75\\

For D)

n=(28+7)/4=8.75\\

Only A) and B)  only A and B meet the requirement

4 0
2 years ago
Austin has two Marvel posters he wants to hang on the wall in his bedroom. The wall is 16.5 feet wide and each poster is 5 3/4 f
vekshin1

The expression for the distance is w=5/3 ft

Step-by-step explanation:

The wall has a width of 16.5 feet

A single poster has a width of 5 3/4 ft which is equal to 23/4 ft or 5.75 ft

For the two posters, the width occupied is ; 23/4 * 2 = 23/2 = 11.5 ft

Remaining width that will be unoccupied by the posters will be 16.5-11.5=5

A sketch of the wall with the two posters such that the edge of the wall is the same as the distance between the posters will show three un-covered spaces, from edge of wall to the first poster, then between the two posters, and lastly from the second poster to the other edge of the wall.

The un-covered 3 portions have an equal width, lets assume that they have a width of w ft

This means 3w will represent the uncovered width which equals to the unoccupied space of 5 ft

Form equation for the uncovered width as;

3w=5ft

w=5/3 ft ---------the distance from the edge of each poster to the nearest edge of wall.

Learn More

Perimeter of a wall : brainly.com/question/12692838

Keyword :posters, wall, edge, distance

#LearnwithBrainly

6 0
3 years ago
PLEASE HELP I’LL MAKE YOU BRAINLIEST! (PLEASE WRITE THE CALCULATIONS ASWELL!)
Elena-2011 [213]

Answer:

Multiply each as in like 120 multiply by 1.2. If 60 multiply by 0.6.

Step-by-step explanation:

6 0
2 years ago
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