SInce you need 1.5 feet of overhang, add 3 feet to each axis dimension 1.5 on each side):
Minor Axis = 18 + 3 = 21 feet
Major axis = 25 + 3 = 28 feet
The area of an ellipse is found by multiplying half the minor axis by half the major axis by PI.
1/2 minor axis = 21 / 2 = 10.5
1/2 major axis = 28 / 2 = 14
Using 3.14 for PI
Area = 10.5 x 14 x 3.14 = 147 x 3.14 = 461.6 sq ft
Answer:
48 + 18√13 cm²
Step-by-step explanation:
HC = BC/2 = 4m/2 = 2 m
AC = √AH² + HC² = √9 + 4 = √13
A = 2×A(ABC) + 2×A(ACFD) + A(BCFE)
= 2×AH×BC/2 + 2×AC×CF + BC×CF
= 2×3×4/2 + 2×√13×9 + 4×9
=12 + 18√13 + 36
= 48 + 18√13 cm²
x=4
Step-by-step explanation:
2log(x)+log(5)=log(80)
log(x^2)+log(5)=log(80)
log(5x^2)=log(80)
5x^2 =80
x^2 =80/5
x^2=16 , taking square root both sides
x=√16
=4
Step-by-step explanation:
Number 3
cos∅ = adj/hyp
cos35° = 20/x
x = 20/cos35°
x = 20/0.8192
x = 24.4155
x ≈ 24.4 to the nearest tenth
Option C
Number 6
tan∅ = opp/adj
tan37° = 20/x
x = 20/tan37°
x = 20/0.7536
x = 26.5409
x ≈ 26.5 to the nearest tenth
Option B
