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3 years ago

The product of x and 3

Mathematics

2 answers:

Vinvika [58]3 years ago

8 0

3 multiplied by X is equal to 3xX which is equal to 3X because that is how algebra works

Ne4ueva [31]3 years ago

5 0

Answer:

3x- we need to know what x is to go any further

Step-by-step explanation:

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Find f(5) please explain

kirza4 [7]

Answer:

-1

Step-by-step explanation:

A function is represented by the following symbol f(x) where f(x) further represents y like this ,

$y=f(x)$

so in this question they are asking what is f(5) which means when the value of x is 5 what is the value of y?

We can see in the graph when x = 5 the value of y is -1 to be exact so

f(5) = -1

$y=f(x)\\-1 = f(5)\\$

8 0

3 years ago

Need the answer right now

hodyreva [135]

Answer:

Diameter is 19

Step-by-step explanation:

6 0

3 years ago

Which equation can pair with X- y=-2 to create a consistent and dependent system?

OLEGan [10]

D is the correct answer to this question

5 0

3 years ago

Discuss the validity of the following statement. If the statement is always true, explain why. If not, give a counterexample.

Zigmanuir [339]

Answer:

$P(E \cup F)=P(E)+P(F)$ .

Step-by-step explanation:

Given the statement

If $P(E)+P(F)=P(E \cup F)+P(E \cap F)$ , then E and F are mutually exclusive events.

If two events are mutually exclusive, they have no elements in common. Thus, P(E∩F)=0.

Therefore, the statement is always true as P(E∩F)=0

For mutually exclusive events:

$P(E \cup F)=P(E)+P(F)$ .

3 0

3 years ago

Solve by using square root: <br> 4(x-1)^2+2=10

Scilla [17]

$4(x-1)^2+2=10\\\\4(x^2-2x+1)+2-10=0\\\\4 x^2-8x+4+2-10=0\\\\4 x^2-8x-4=0\ \ / :4\\\\x^2-2x-1=0\\\\x_{1}=\frac{-b-\sqrt{b^2-4ac}}{2a}=\frac{2-\sqrt{ (-2)^2-4*1*(-1)}}{2 }=\frac{2-\sqrt{ 8}}{2 }=\frac{2- \sqrt{ 4*2}}{2 }=\\\\=\frac{2-\sqrt{ 8}}{2 }=\frac{2(1- \sqrt{ 2})}{2 }=1- \sqrt{ 2}\\\\x_{2}=\frac{-b+\sqrt{b^2-4ac}}{2a}=\frac{2+\sqrt{ (-2)^2-4*1*(-1)}}{2 }=\frac{2(1+ \sqrt{ 2})}{2 }=1+ \sqrt{ 2}$

$Answer:\ x=1- \sqrt{2}\ \ or\ \ x= 1+ \sqrt{ 2}$

3 0

3 years ago

Read 2 more answers