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Harlamova29_29 [7]
3 years ago
6

Please help and i’ll mark you brainliest

Mathematics
2 answers:
Andrews [41]3 years ago
8 0

Answer:

I believe that you multiply the sides together, I may be wrong, I did this before i just forgot!

Step-by-step explanation:

Aleonysh [2.5K]3 years ago
3 0

idk how to help you sorry :(

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HELPP ME PLEASEEE!!<br> explain your thinking on who is correct
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Both

Step-by-step explanation:

They will both give you the same answer.

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What is a fraction of a fraction
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<h3> - - - - - - - - - - - - - ~<u>Hello There</u>!~ - - - - - - - - - - - - - </h3>

➷ When it comes to dividing fractions, there is a rule you must now.

It's called Keep Flip Change.

I'll give you an example:

\frac{2}{7} / \frac{4}{6}

Keep the first fraction exactly as it is

Flip the second fraction upside down (switch the numerator and denominator around)

Change the sign to a multiplication.

This is how it should look:

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Now you just multiply them as you normally would to get an answer of:

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➶Hope This Helps You!

➶Good Luck :)

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3 years ago
Solve the equation for x in terms of c
Dovator [93]

solve\:for\:x,\:\frac{2}{3}\left(cx+\frac{1}{2}\right)-\frac{1}{4}=\frac{5}{2}

\mathrm{Add\:}\frac{1}{4}\mathrm{\:to\:both\:sides}

\frac{2}{3}\left(cx+\frac{1}{2}\right)-\frac{1}{4}+\frac{1}{4}=\frac{5}{2}+\frac{1}{4}

\frac{2}{3}\left(cx+\frac{1}{2}\right)=\frac{11}{4}

\mathrm{Multiply\:both\:sides\:by\:}3

3\cdot \frac{2}{3}\left(cx+\frac{1}{2}\right)=\frac{11\cdot \:3}{4}

2cx+1=\frac{33}{4}

\mathrm{Subtract\:}1\mathrm{\:from\:both\:sides}

2cx+1-1=\frac{33}{4}-1

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\mathrm{Divide\:both\:sides\:by\:}2c

x=\frac{29}{8c}

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