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Mila [183]
3 years ago
9

Joslyn wants to buy 4 packs of pens for $12.00 each and a pack of pencils for &6.00. How much money does she need

Mathematics
1 answer:
seropon [69]3 years ago
8 0
$54 is your answer

You multiply $12.00 by 4 packs of pens and then add $6.00 for the pencils.
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Solve for M.<br><br> 2G/k=5/M
BartSMP [9]

5k/2G is the answer to the problem.

6 0
3 years ago
BRAINLIEST AND POINTS!!!<br><br> PLEASE EXPLAIN
timofeeve [1]

Answer:

Option C. \$23,134.61

Step-by-step explanation:

we know that

A=\frac{P[(1+r)^{n} -1]}{r(1+r)^{n}}

we have

P=\$400

r=0.075/12=0.00625

n=6*12=72\ months

substitute in the formula

A=\frac{400[(1+0.00625)^{72} -1]}{0.00625(1+0.00625)^{72}}\\ \\A=\frac{226.446972}{0.009788}\\ \\A=\$23,134.61

4 0
3 years ago
I tell you these facts about a mystery number, $c$: $\bullet$ $1.5 &lt; c &lt; 2$ $\bullet$ $c$ can be written as a fraction wit
makkiz [27]

Answer:

Possible answer: \displaystyle c = \frac{16}{10} = \frac{8}{5} = 1.6.

Step-by-step explanation:

Rewrite the bounds of c as fractions:

The simplest fraction for 1.5 is \displaystyle \frac{3}{2}. Write the upper bound 2 as a fraction with the same denominator:

\displaystyle 2 = 2 \times 1 = 2 \times \frac{2}{2} = \frac{4}{2}.

Hence the range for c would be:

\displaystyle \frac{3}{2} < c < \frac{4}{2}.

If the denominator of c is also 2, then the range for its numerator (call it p) would be 3 < p < 4. Apparently, no whole number could fit into this interval. The reason is that the interval is open, and the difference between the bounds is less than 2.

To solve this problem, consider scaling up the denominator. To make sure that the numerator of the bounds are still whole numbers, multiply both the numerator and the denominator by a whole number (for example, 2.)

\displaystyle \frac{3}{2} = \frac{2 \times 3}{2 \times 2} = \frac{6}{4}.

\displaystyle \frac{4}{2} = \frac{2\times 4}{2 \times 2} = \frac{8}{4}.

At this point, the difference between the numerators is now 2. That allows a number (7 in this case) to fit between the bounds. However, \displaystyle \frac{1}{c} = \frac{4}{7} can't be written as finite decimals.

Try multiplying the numerator and the denominator by a different number.

\displaystyle \frac{3}{2} = \frac{3 \times 3}{3 \times 2} = \frac{9}{6}.

\displaystyle \frac{4}{2} = \frac{3\times 4}{3 \times 2} = \frac{12}{6}.

\displaystyle \frac{3}{2} = \frac{4 \times 3}{4 \times 2} = \frac{12}{8}.

\displaystyle \frac{4}{2} = \frac{4\times 4}{4 \times 2} = \frac{16}{8}.

\displaystyle \frac{3}{2} = \frac{5 \times 3}{5 \times 2} = \frac{15}{10}.

\displaystyle \frac{4}{2} = \frac{5\times 4}{5 \times 2} = \frac{20}{10}.

It is important to note that some expressions for c can be simplified. For example, \displaystyle \frac{16}{10} = \frac{2 \times 8}{2 \times 5} = \frac{8}{5} because of the common factor 2.

Apparently \displaystyle c = \frac{16}{10} = \frac{8}{5} works. c = 1.6 while \displaystyle \frac{1}{c} = \frac{5}{8} = 0.625.

8 0
3 years ago
Read 2 more answers
Suppose that 13 inches of wire cost 39 cent how much would 8 inches cost
Feliz [49]

Answer:

24 cent

Step-by-step explanation:

If 13 inches of wire cost 39 cent.

We have to calculate how much 1 inch of wire would cost first, before determining the cost of 8 inches of wire.

If 13 inches of wire costs 39cents, Then 1 inch of wire would cost 3 cent.

That is 39/13, which gives 3.

If 1 inch of wire cost 3 cents. Two inches of wire would cost 6 cents we 3 inches of wire costs 9 cents.

To get the cost of 8 inches of wire, we therefore multiply 8 by 3, which gives 24.

8 inches of wire costs 24 cents.

7 0
3 years ago
Colby adds 1 2/3 cups of flour to his mixing bowl and then realizes he put too much.He takes 1/4 cup of flour back out of the bo
galben [10]

Answer:

The quantity of flour need by Colby's recipe is  1\frac{5}{12} cups.

Step-by-step explanation:

Given: Colby adds 1\frac{2}{3} cups of flour to his mixing bowl and then realizes he put too much.He takes\frac{1}{4} cup of flour back out of the bowl.

We have to find the quantity of flour need by Colby's recipe.

The quantity of flour need by Colby's recipe = Number of flour cups Colby added - number of flour cups Colby taken out.

that is,

Number of flour cups Colby added = 1\frac{2}{3}=\frac{5}{3}

Number of flour cups Colby taken out = \frac{1}{4}

The quantity of flour need by Colby's recipe = \frac{5}{3}-\frac{1}{4}

taking LCM, we get, LCM(3,4) =12

The quantity of flour need by Colby's recipe = \frac{20-3}{12}

The quantity of flour need by Colby's recipe = \frac{17}{12}=1\frac{5}{12}

Thus, The quantity of flour need by Colby's recipe is  1\frac{5}{12} cups.

7 0
3 years ago
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