Answer:
Step-by-step explanation:
1) Step 4: Marc has converted radical form to exponent form
Step 5: He has evaluated the value of the radical
3)
![x = \sqrt[3]{8}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%5B3%5D%7B8%7D)
Here, 3 is index and 8 is radicand.
Prime factorize 8 and for every 3 numbers we can take one number outside the radical
Solution:
![x = \sqrt[3]{2*2*2}\\\\x = 2](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%5B3%5D%7B2%2A2%2A2%7D%5C%5C%5C%5Cx%20%3D%202)
4) No,my equation does not have an extraneous solution.
My solution, satisfies the equation
The prime number you are looking for is 141
Answer:
1. Y
2. N
3. N
4. N
Step-by-step explanation:
Let's use the second equation, since it seems to be easier to use.
To check if an ordered pair is a solution, plug it in to the equation.
1. 
--> Y
2. 
--> N
3. 
--> N
4. 
--> N
Edit : The 4th equation doesn't work for the first equation, whereas the first one still does.
-3. Put the two equation equal to each other and solve.
4x+18=2x+12
-2x=-2x
2x+18=12
-18=-18
2x=-6
2x/2=-6/2
x=-3
