1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
sergey [27]
2 years ago
14

Donna read 18 out of 30 pages in her book.What percent of the book did she read?​

Mathematics
2 answers:
inysia [295]2 years ago
6 0

Answer:

60

Step-by-step explanation:

18 /30 is .6. So the answer would be 60 percent

bazaltina [42]2 years ago
6 0

Answer:

60%

Step-by-step explanation:

1.Divide 18 and 30 by 3

  • 6 and 10

2. Multiply each number by 10

  • 60 and 100

3.Put it as a fraction

  • \frac{60}{100}=0.6=<u>60%</u>

<u></u>

<u>Hope this helped! :)</u>

You might be interested in
An article suggests that a poisson process can be used to represent the occurrence of structural loads over time. suppose the me
kirill115 [55]

Answer:

a) \lambda_1 = 2*2 = 4

And let X our random variable who represent the "occurrence of structural loads over time" we know that:

X(2) \sim Poi (4)

And the expected value is E(X) = \lambda =4

So we expect 4 number of loads in the 2 year period.

b) P(X(2) >6) = 1-P(X(2)\leq 6)= 1-[P(X(2) =0)+P(X(2) =1)+P(X(2) =2)+...+P(X(2) =6)]

P(X(2) >6) = 1- [e^{-4}+ \frac{e^{-4}4^1}{1!}+ \frac{e^{-4}4^2}{2!} +\frac{e^{-4}4^3}{3!} +\frac{e^{-4}4^4}{4!}+\frac{e^{-4}4^5}{5!}+\frac{e^{-4}4^6}{6!}]

And we got: P(X(2) >6) =1-0.889=0.111

c)  e^{-2t} \leq 2

We can apply natural log in both sides and we got:

-2t \leq ln(0.2)

If we multiply by -1 both sides of the inequality we have:

2t \geq -ln(0.2)

And if we divide both sides by 2 we got:

t \geq \frac{-ln(0.2)}{2}

t \geq 0.8047

And then we can conclude that the time period with any load would be 0.8047 years.

Step-by-step explanation:

Previous concepts

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution". The probability density function is given by:

P(X=x)=\lambda e^{-\lambda x}

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution"

Solution to the problem

Let X our random variable who represent the "occurrence of structural loads over time"

For this case we have the value for the mean given \mu = 0.5 and we can solve for the parameter \lambda like this:

\frac{1}{\lambda} = 0.5

\lambda =2

So then X(t) \sim Poi (\lambda t)

X follows a Poisson process

Part a

For this case since we are interested in the number of loads in a 2 year period the new rate would be given by:

\lambda_1 = 2*2 = 4

And let X our random variable who represent the "occurrence of structural loads over time" we know that:

X(2) \sim Poi (4)

And the expected value is E(X) = \lambda =4

So we expect 4 number of loads in the 2 year period.

Part b

For this case we want the following probability:

P(X(2) >6)

And we can use the complement rule like this

P(X(2) >6) = 1-P(X(2)\leq 6)= 1-[P(X(2) =0)+P(X(2) =1)+P(X(2) =2)+...+P(X(2) =6)]

And we can solve this like this using the masss function:

P(X(2) >6) = 1- [e^{-4}+ \frac{e^{-4}4^1}{1!}+ \frac{e^{-4}4^2}{2!} +\frac{e^{-4}4^3}{3!} +\frac{e^{-4}4^4}{4!}+\frac{e^{-4}4^5}{5!}+\frac{e^{-4}4^6}{6!}]

And we got: P(X(2) >6) =1-0.889=0.111

Part c

For this case we know that the arrival time follows an exponential distribution and let T the random variable:

T \sim Exp(\lambda=2)

The probability of no arrival during a period of duration t is given by:

f(T) = e^{-\lambda t}

And we want to find a value of t who satisfy this:

e^{-2t} \leq 2

We can apply natural log in both sides and we got:

-2t \leq ln(0.2)

If we multiply by -1 both sides of the inequality we have:

2t \geq -ln(0.2)

And if we divide both sides by 2 we got:

t \geq \frac{-ln(0.2)}{2}

t \geq 0.8047

And then we can conclude that the time period with any load would be 0.8047 years.

3 0
3 years ago
Can someone solve and explain this question plz​
oee [108]

firstly let's convert the mixed fraction to improper fraction, then hmmm let's see we have two denominators, 5 and 3, and their LCD will simply be 15, so we'll multiply both sides by that LCD to do away with the denominators, let's proceed,

\bf \stackrel{mixed}{2\frac{1}{3}}\implies \cfrac{2\cdot 3+1}{3}\implies \stackrel{improper}{\cfrac{7}{3}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{z}{5}-4=\cfrac{7}{3}\implies \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{15}}{15\left( \cfrac{z}{5}-4 \right)=15\left( \cfrac{7}{3} \right)}\implies 3z-60=35 \\\\\\ 3z=95\implies z=\cfrac{95}{3}\implies z = 31\frac{2}{3}

4 0
3 years ago
An educational psychologist wishes to know the mean number of words a third grader can read per minute. She wants to make an est
amid [387]

Answer:

(38.1,88.6)

Step-by-step explanation:

We are given the following in the question:

Sample mean, \bar{x} = 38.3

Sample size, n = 695

Alpha, α = 0.05

Population standard deviation, σ = 3.6

95% Confidence interval:

\mu \pm z_{critical}\frac{\sigma}{\sqrt{n}}

Putting the values, we get,

z_{critical}\text{ at}~\alpha_{0.05} = 1.96

38.3 \pm 1.96(\frac{3.6}{\sqrt{695}} ) = 38.3 \pm 0.267 = (38.033,38.567) \approx (38.1,88.6)

8 0
3 years ago
I need help!! What is he answer??
IgorC [24]
2 is the answer i think
7 0
3 years ago
A gym charges $25 per month plus extra four dollars to swim in a pool for an hour if a member only has $45 to spend each month a
NeTakaya

Answer:

5 hours

Step-by-step explanation:

So the set fee is 25. 45-25 = 20. Now, 4 dollars an hour. 20/4 = 5, so 5 hours

8 0
2 years ago
Other questions:
  • (-a)^3 in expanded form?
    15·1 answer
  • Sam studied guinea pigs for his science fair project. He found that the amount of weight the guinea pigs gained varied directly
    14·1 answer
  • Convert 0.000002954 to scientific notation.
    13·2 answers
  • A scientist builds a Mars rover that can travel 4.9 centimeters per second on flat ground.
    12·1 answer
  • Whats the answer for -2x+11+6x ?
    9·1 answer
  • PLZ HELPPPPPPPPPPPPPPPP
    7·2 answers
  • Can someone help me on this.
    6·2 answers
  • What is the measure compliment for 57 degrees
    5·1 answer
  • Find the product.<br><br> (23)(−98)(−45)(−1)<br> Enter the correct product in the box.
    6·1 answer
  • Rashid solves the following system of equations using the elimination method.
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!