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Elanso [62]
3 years ago
5

Identify the sequence as arithmetic or geometric, and write a recursive formula for the sequence. Be

Mathematics
1 answer:
sasho [114]3 years ago
8 0

Answer:

The sequence is arithmetic.

\texttt{Recursive formula, }t_n=t_{n-1}+10      

Step-by-step explanation:

If the sequence is arithmetic common difference will be same, if the sequence is arithmetic common ratio will be same.

Here the sequence is −101, −91, −81, −71, …

       Difference between terms

                                         -91 - (-101) = 10

                                         -81 - (-91) = 10

                                         -71 - (-81) = 10

      They are same , so the sequence is arithmetic.

Common difference, d = 10

Now we need to find recursive formula for the sequence.

Recursive formula for GP

                      t_n=t_{n-1}+d

\texttt{Recursive formula, }t_n=t_{n-1}+10              

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Point M is the midpoint of AB. The coordinates of point A are (−7, 1) and the coordinates of M are (−2, 2). What are the coordin
notka56 [123]

Answer:

\huge{\boxed{\sf{ ( 3 , 3 ) }}}

Step-by-step explanation:

Co-ordinates of point A = ( -7 , 1 )

Co-ordinates of point M = ( -2 , 2 )

Let the co-ordinates of point B be ( x , y )

A ( -7 , 1 ) \longrightarrow ( x1 , y1 )

B ( x , y ) \longrightarrow ( x2 , y2 )

Now,

Midpoint = (\frac{x1 + x2}{2}  , \frac{y1 + y2}{2} )

⇒( -2 , 2 ) = ( \frac{-7 + x}{2}  , \frac{1 + y}{2} )

Finding the value of x :                    

⇒-2 = \frac{-7 + x}{2}

Do cross multiplication                

⇒-4 = -7 + x

⇒-7 + x = -4

⇒x = -4 + 7

⇒x = 3

Now, finding the value of y

⇒2 = \frac{1+y}{2}

Do cross multiplication

⇒4 = 1+y

⇒1+y = 4

⇒y = 4 - 1

⇒y = 3

Hence, The co-ordinates of point B = ( 3 , 3 )

Hope I helped!

Best regards!

~\text{ TheAnimeGirl}

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