Solution
The table below is the required sample space of the to fair die
From the above table
The sample space contain 36 outcomes
Event A: The sum is greater than 9
we will look at the table and count all the elements that are greater than 9
There are 6 elements (they are 10, 10, 10, 11, 11, 12 from the table)
The probability for event A will be

P(A) = 1/6
Event B: The sum is an even number.
We will look at the table and count the number of elements that are even
There are 18 elements (notice that there are 3 even number on each of the 6 rows of the table)
The probability for event B will be

p(B) = 1/2
Answer:
5
Step-by-step explanation:
6.270,6.270, 6.026,6.26, 6.3,
Answer:
b = 10
Step-by-step explanation:
P = 2 (l + b)
l = 15
P = 50
Substitute
50 = 2 (15 + b)
multiply
50 = 30 + 2b
subtract
20 = 2b
divide
b = 10