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frez [133]
3 years ago
10

Find the derivative g(x)=ln(2x^2+1)

Mathematics
1 answer:
lana [24]3 years ago
8 0

Answer:

4x / (2x^2+1)

Step-by-step explanation:

g(x)=ln(2x^2+1)

Using u substitution

u= 2x^2 +1

du = 4x  dx

g'(x) = d/du ( g(u) du)

We know that the derivative of ln(u) = 1/u  since this is always positive

        = 1/ u* du

 Substituting x back into the equation

g'(x) = 1/(2x^2+1) * 4x

       = 4x / (2x^2+1)

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Which ordered pair is a solution to the system of equations?
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(- 2, - 3) is a solution to the given system of equations.

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<u>Step-by-step explanation:</u>

Given equation are not presented in proper format. So, let assume the given system of are as below,

         2 x - y = -1

         2 x -4 y = 8

Now, subtract the second equation from the first, we get

          (2 x - y) -(2 x - 4 y) = -1 -8

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           y = -3 (obtained this when divide by 3)

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Now, the answer is (x, y) = (- 2, - 3)

3 0
3 years ago
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Nesterboy [21]

A. The angles at the intersection of the two lines can be proven to be congruent and complementary . so they meet at a right angle and the lines are perpendicular.

<u>Step-by-step explanation:</u>

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-3s + 5 = s + 13 <br>In a linear equation​
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S= -2
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3 years ago
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